Class 11th
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New answer posted
2 months agoContributor-Level 10
Since significant figures show the degree of correctness of any measurement, so in any mathematical calculation we cannot increase the number of significant digits. Because the four reading has 3 significant digits so the answer should also have 3 significant digits only.
New answer posted
2 months agoContributor-Level 10
f? = 420 Hz
f? = (V? + V)/ (V? - V) f? = 490
(330 + V)/ (300 - V) 420 = 490
(330 + V)6 = 7 (330 – V)
13 V = 330
V = 33/13 (m/s)
= 91 (km/hr)
New answer posted
2 months agoContributor-Level 10
sx? dg (x? /2) + sx? dg (x? /2)
Uf = (S (x? +x? )/2)gd (x? +x? )/4) x 2
= S (x? + x? )²gd/4
U? -Uf = (Sgd/4) {2x? ² + 2x? ² − (x? + x? )²}
= (Sgd/4) (x? -x? )²
New answer posted
2 months agoNew answer posted
2 months agoContributor-Level 10
mdv? /dt = kv? (1) and mdv? /dt = kv?
(2)/ (1) ⇒ dv? /dv? = v? /v?
v? dv? = v? dv?
v? ² = v? ² + C
v? ² – v? ² = C = Constant
Now, v? * a? = (v? î + v? ) * (k/m) (v? î + v? )
= (k/m) [v? ²k? – v? ²k? ] = (k/m) (v? ² – v? ²)k? = Constant.
New answer posted
2 months agoContributor-Level 10
l? = 0.6M
l? = 0.8M
√l? ² + l? ² = 1
MI about 0 = M/12 (l? ² + l? ²)
I? = M/12
MI about O' = M/12 (l? ² + l? ²) + M (l? ²+l? ²)/4
I? = M/12 + M/4 = (4m)/12; I? /I? = 1/4
New answer posted
2 months agoContributor-Level 10
x = (IFV²)/ (WL? )
I = [ML²]
F = [MLT? ²]
V² = [L² T? ²]
W = [ML² T? ²]
Q? = [L? ]
X = [ML? ¹ T? ²]
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