Class 11th

Get insights from 8k questions on Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 11th

Follow Ask Question
8k

Questions

0

Discussions

38

Active Users

0

Followers

New answer posted

2 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

dm = λdx = λ? (1 + x/L)dx
M = ∫? λ? (1 + x/L)dx = λ? [L + L²/2L] = 3λ? L/2
dI = dmx² = λ? (1 + x/L)dx * x²
I = λ? ∫? (x² + x³/L)dx = λ? [L³/3 + L? /4L]
I = (7λ? L³)/12 = (7/12) * (2M/3L) * L³ = (7/18)ML²

New answer posted

2 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Distance moved = Area under curve
= ½ * 8 * 5 = 20

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Mean relaxation time T = λ/V? = λ / √ (8RT/πm)
∴ T ∝ 1/√T

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

B (ΔV/V) = ΔP
ΔV/V = ΔP/B = (4 x 10? )/ (8 x 10¹? ) = 1/20
V = l³
dV = 3l² dl
dV/V = 3l²dl/l³ = 3dl/l
ΔV/V = 3 (Δl/l); 1/20 = 3 (Δl/l); ΔV/V = 1/60

% (Δl/l) = 100/60 = 1.67%

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

ΔQ = heat supplied
ΔW = work done
ΔU = change in internal energy
(i) adiabatic (B) Δθ = 0
(ii) isothermal (D) ΔU = 0
(iii) isochoric (A) ΔW = 0
(iv) isobaric (C) ΔU ≠ 0, ΔW ≠ 0, ΔQ ≠ 0

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 16 Views

V
Vishal Baghel

Contributor-Level 10

Mg + MkV² = MA = -mv (dV/dx)
Vdv = (−) (g + kV²)dx
∫? (Vdv)/ (g + kv²) = ∫? - dx
[ln (g + kV²)/2k]? = -x
ln (g/ (g + ku²) = −2kx
x = (1/2k)ln (1 + ku²/g)

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Using Bernoulli's equation
P? + (1/2)ρv? ² + ρgh? = P? + (1/2)ρv? ² + ρgh?
For horizontal tube h? = h?
P + (1/2)ρv² = P/2 + (1/2)ρV²
(1/2)ρV² = P/2 + (1/2)ρv²
V = √ (P/ρ + v²)

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Escape velocity = √ (2GM/R) = v? f
Orbital speed = √ (GM/R) = V?
V? /V? = 1/√2

New answer posted

2 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Network done is equal to area under F-x curve
= 200 x 15 + ½ x 100 x 15 + 100 * 15
= 4500 + 750
= 5250

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.