Class 11th
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New answer posted
2 months agoContributor-Level 9
eq of H? O? = eq of KMnO?
(0.316 / 158) x 5 = 0.01
(0.01 x 17 / 0.2) x 100 = 85%
New answer posted
2 months agoContributor-Level 10
(i) 2Fe²? + H? O? → 2Fe³? + 2OH?
(ii) 2MnO? + 5H? O? + 6H? → 2Mn²? + 5O? + 8H? O
So sum of (x + y + x¹ + y¹ + z¹) = 2 + 2 + 2 + 5 + 8 = 19
New answer posted
2 months agoContributor-Level 10
For hydrogen atom :
For Lyman series n? = 1 & n? = ∞
1/λH = RH [1/1² - 1/∞²] So, λ = 1/RH
For He? ion Balmer series n? = 2 & n? = 3
1/λHe? = RH * Z² [1/n? ² - 1/n? ²]
1/λHe? = RH * 4 * [1/4 - 1/9] = RH * 4 * (5/36)
1/λHe? = (5/9)RH = (5/9) (1/λ)
(λHe? ) = (9/5)λ
New answer posted
2 months agoContributor-Level 9
N? + 3H? → 2NH?
(2.8 x 10³) / 28 → 0.1 x 10³ mol LR
(1 x 10³) / 2 → 0.5 x 10³ mol
Mass of NH? produced = 0.2 * 10³ * 17 = 3.4 kg = 3400 g
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