Class 11th

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New answer posted

7 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

f? = 420 Hz
f? = (V? + V)/ (V? - V) f? = 490
(330 + V)/ (300 - V) 420 = 490
(330 + V)6 = 7 (330 – V)

13 V = 330
V = 33/13 (m/s)
= 91 (km/hr)

New answer posted

7 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

sx? dg (x? /2) + sx? dg (x? /2)
Uf = (S (x? +x? )/2)gd (x? +x? )/4) x 2
= S (x? + x? )²gd/4
U? -Uf = (Sgd/4) {2x? ² + 2x? ² − (x? + x? )²}
= (Sgd/4) (x? -x? )²

New answer posted

7 months ago

0 Follower 53 Views

R
Raj Pandey

Contributor-Level 9

At equilibrium rate of forward and backward reaction becomes equal.

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 19 Views

A
alok kumar singh

Contributor-Level 10

mdv? /dt = kv? (1) and mdv? /dt = kv?
(2)/ (1) ⇒ dv? /dv? = v? /v?
v? dv? = v? dv?
v? ² = v? ² + C
v? ² – v? ² = C = Constant
Now, v? * a? = (v? î + v? ) * (k/m) (v? î + v? )
= (k/m) [v? ²k? – v? ²k? ] = (k/m) (v? ² – v? ²)k? = Constant.

New answer posted

7 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

l? = 0.6M
l? = 0.8M
√l? ² + l? ² = 1
MI about 0 = M/12 (l? ² + l? ²)
I? = M/12

MI about O' = M/12 (l? ² + l? ²) + M (l? ²+l? ²)/4
I? = M/12 + M/4 = (4m)/12; I? /I? = 1/4

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

KIndly go through the solution

 

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

x = (IFV²)/ (WL? )
I = [ML²]
F = [MLT? ²]
V² = [L² T? ²]
W = [ML² T? ²]
Q? = [L? ]
X = [ML? ¹ T? ²]

New answer posted

7 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

I = 0.8 kgM², |μ? | = 20Am²
U? = -μ? ⋅ B? = 0
Uf = -μBcos (30°) = -20 x 4 x √3/2
U? – Uf = 40√3 = ½ I ω² = 0.4ω²
ω² = 100√3; ω = 10 (3¹/? )

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