Class 11th
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New answer posted
7 months agoContributor-Level 10
In isoelectronic species nuclear charge can be approximated as
Nuclear charge ≈ z / no. of electrons
Al³? Mg²? Na? F? O²? N³?
Nuclear Charge: 13/10 12/10 11/10 9/10 8/10 7/10
Minimum nuclear charge is in N³? and maximum is in Al³?
So order should be
Al³? < Mg? < Na? < F? < O? < N?
New answer posted
7 months agoContributor-Level 10
Using VSEPR, L.P - B.P repulsion we can safely say that CH? should have the highest bond angle among the given
New answer posted
7 months agoContributor-Level 10
P = constant
m (dv/dt) = P
∫? vdv = P/m ∫? dt
v²/2 = Pt/m ⇒ v = (2Pt/m)¹/²
dx/dt = √ (2P/m) t¹/²
∫? dx = √ (2P/m) ∫? t¹/² dt
x = √ (2P/m) (t³/² / (3/2) = √ (2P/m) * (2/3) * t³/²
= (2/3) * 27 = 18
New answer posted
7 months agoContributor-Level 10
V_rms = √ (3RT/M)
V_N? = V_H?
√ (3RT_N? / M_N? ) = √ (3RT_H? / M_H? )
573/28 = T_H? /2
⇒ T_H? = 40.928
New answer posted
7 months agoContributor-Level 10
L_i = L_f
mvL = Iω
mvL = (ML³/3 + mL²)ω
Before collision
After collision
0.1 * 80 * 1 = (0.9 * 1²)/3 + 0.1 * 1²)ω
8 = (3/10 + 1/10)ω 8 = (4/10)ω ω = 20 rad/sec
New answer posted
7 months agoContributor-Level 10
Area of OABS is A?
Area of SCD is A?
Distance = |A? | + |A? |
A? = (1/2) [13/3 + 1]4 = 32/3
A? = (1/2) * 5/3 * 2 = 5/3
Distance = |A? | + |A? |
= 32/3 + 5/3 = 37/3
New answer posted
7 months agoContributor-Level 10
Moment of inertia in case (i) is I?
Moment of inertia in case (ii) is I?
I? = 2MR²
I? = (3/2)MR²
T? = 2π√ (I? /Mgd); T? = 2π√ (I? /Mgd)
T? /T? = √ (I? /I? ) = √ (2MR² / (3/2)MR²) = 2/√3
New answer posted
7 months agoContributor-Level 10
√2gh = (2r²g/9η) (ρ_t - ρ)
⇒ h = (2/81) (r? g (ρ_t - ρ)²/η²)
⇒ h ∝ r?
After falling through h, the velocity be equal to terminal velocity.
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