Class 11th

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New answer posted

3 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

 

= A + B (say)

(1 + x)15 =

differentiating 15 (1 + x)14 =   r.15Crxr1

put  = x = -1

0 = 1 5 C 1 + 2 . 1 5 C 2 . . . . . . . = A      

B = 1 4 C 1 3 = 2 1 3    

A + B = 2 1 3 1 4     

New answer posted

3 months ago

0 Follower 20 Views

V
Vishal Baghel

Contributor-Level 10

Total oscillation = 1 2 + 1 8 = 5 8

t i m e t a k e n = T 2 + T 1 2 = 7 T 1 2

= 7

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Let direction ratio of the normal to the required plane are l, m, n

3 l + m 2 n = 0 2 l 5 m n = 0 l 1 1 = m 1 = n 1 7             

Equation of required plane

11 (x – 1) + 1 (y – 2) + 17 (z + 3) = 0

          

New answer posted

3 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Time period of second pendulum is 2 seconds.                                                                                                                                                                          &nbs

...more

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Any point on line  x 3 1 = y 4 2 = z 5 2 = r is P (r + 3, 2r + 4, 2r + 5) lies on x + y + z = 17,

5r + 12 = 17

r = 1

P ( 4 , 6 , 7 ) A ( 1 , 1 , 9 ) d i s t A P = 9 + 2 5 + 4 = 3 8  

 

New answer posted

3 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

x2 + y2 = 36         ……(i)

y2 = 9x      .(ii)

Solving (i) & (ii)

x2 + 9x – 36 = 0

(x + 12) (x – 3) = 0

x = 3

Let A = 0 3 ( 3 6 x 2 3 x ) d x  

= [ x 3 6 x 2 2 + 1 8 s i n 1 x 6 ] 0 3 3 . x 3 / 2 3 / 2 ] 0 3       

= 3 π 3 3 2        

Required area = = 1 2 π ( 6 ) 2 + 2 ( 3 π 3 3 2 ) = ( 2 4 π 3 3 ) s q . u n i t

 

          

New answer posted

3 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

v=ωk=301=30m/s

v=TμT=μv2=0.135*103102* (30)2=12.15N=1215*102N

New answer posted

3 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

mg – N = ma

N = m (g – a) = 60 * (10 – 1.8) = 60 * 8.2 = 492 N

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

f ( x ) = 2 x 1 g : R { 1 } R        

g ( x ) = x 1 / 2 x 1           

f { g ( x ) } = 2 ( x 1 / 2 x 1 ) 1 = 2 x 1 x + 1 x 1 = x x 1 , x 1           

y = x x 1 x = y y 1 y 1           

One – one but not onto

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

U = 3PV + 4

n C v T = 3 P V + 4

n * f R T 2 = 3 P V + 4

f = 6 + 8 P V

f > 6 p o l y a t o m i c

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