Tags Class 11th

Class 11th

Get insights from 8k questions on Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 11th

Follow Ask Question

Questions

Discussions

Active Users

Followers

New answer posted

11 months ago

Class 11th Physics

If the rms speed of oxygen molecules at 0°C is 160 m/s, find the rms speed of hydrogen molecules at 0°C.

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

$\frac{{(v_{r m s})}_{O_{2}}}{(v_{r m s}) H_{2}} = \sqrt[]{\frac{M_{H_{2}}}{M_{O_{2}}}} = \sqrt[]{\frac{2}{32}}$

$\Rightarrow {(v_{r m s})}_{H_{2}} = 4 * {(v_{r m s})}_{O_{2}} = 4 * 160 = 640 m / s$

0 0

New answer posted

11 months ago

Class 11th Work, Energy and Power

Two persons A and B perform same amount of work in moving a body through a certain distance d with application of forces acting at angle 45° and 60° with the direction of displacement respectively. The ratio of force applied by person A to the force applied by person B is $\frac{1}{\sqrt[]{x}} .$ The value of x is

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

W_A = W_B

$\Rightarrow F_{A} * d * c o s 45 = F_{B} * d * c o s 60$

$\Rightarrow \frac{F_{A}}{F_{B}} = \frac{1}{\sqrt[]{2}} = \frac{1}{\sqrt[]{x}}$

=> x = 2

0 0

New answer posted

11 months ago

Class 11th Physics Motion in Straight Line

If the velocity of a body related to displacement x is given by $υ = \sqrt[]{5000 + 24 x} m / s,$ then the acceleration of the body is…….

0 Follower 4 Views

Vishal Baghel

Contributor-Level 10

$a = V \frac{d v}{d x}$

$\Rightarrow a = \sqrt[]{5000 + 24 x} * \frac{12}{\sqrt[]{5000 + 24 x}}$

=> a = 12 m/s²

0 0

New answer posted

11 months ago

Class 11th Physics

A body of mass (2M) splits into four masses {m, M – m, m, M – m}, which are rearranged to form a square as shown in the figure. The ratio of $\frac{M}{m}$ for which, the gravitational potential energy of the system becomes maximum is x : 1. The value of x is

0 Follower 30 Views

Vishal Baghel

Contributor-Level 10

$U = - \frac{G m (M - m)}{d} * 4 + 2 x - (\frac{G m^{2}}{\sqrt[]{2} d})$

For Umax

$\frac{d U}{d m} = 0 \Rightarrow m = \frac{M}{2} \Rightarrow \frac{M}{m} = 2$

0 0

New answer posted

11 months ago

Class 11th Units and Measurement

If force (F), length (L) and time (T) are taken as the fundamental quantities. Then what will be the dimension of density:

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

$[F] = M L T^{- 2} \Rightarrow M = F L^{- 1} T^{2}$

$[ρ] = M L^{- 3} = F L^{- 1} T^{2} L^{- 3} = F L^{- 4} T^{2}$

0 0

New answer posted

11 months ago

Class 11th Waves

Two cars X and Y are approaching each other with velocities is 36 km/h and 72 km/h respectively . The frequency of a whistle sound as emitted by a passenger in car X, heard by the passenger in car Y is 1320 Hz. If the velocity of sound in air is 340 m/s, the actual frequency of the whistle sound produced is……….Hz.

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$f^{1} = f_{0} * [\frac{340 + 20}{340 - 10}] = 1320$

=> f₀ = 1210 Hz

0 0

New answer posted

11 months ago

Class 11th Physics

A rod CD of thermal resistance 10.0 KW^-¹ is joined at the middle of an identical rod AB as shown in figure. The end A, B and D are maintained at 200°C, 100°C and 125°C respectively. The heat current in CD in P watt. The value of P is……. .

0 Follower 11 Views

Vishal Baghel

Contributor-Level 10

$\Rightarrow H_{1} = H_{2} + H_{3}$

$\frac{200 - T}{5} = \frac{T - 125}{10} + \frac{T - 100}{5}$

$\Rightarrow T = 145 ° C \Rightarrow H_{2} = \frac{145 - 125}{10} = 2 W$

0 0

New answer posted

11 months ago

Class 11th Physics System of Particles and Rotational Motion

Two discs have moments of inertia I₁ and I₂ about their respective axes perpendicular to the plane and passing through the centre. They are rotating with angular speeds, $ω_{1}$ and $ω_{2}$ respectively and are brought into contact face to face with their axes of rotation coaxial. The loss in kinetic energy of the system in the process is given by:

0 Follower 3 Views

alok kumar singh

Contributor-Level 10

From Conservation of Angular Momentum

$\Rightarrow l_{1} ω_{1} + l_{2} ω_{2} = (l_{1} + l_{2}) ω$

$ω = \frac{l_{1} ω_{1} + l_{2} ω_{2}}{l_{1} + l_{2}}$

$K E_{i} = \frac{1}{2} l_{1} ω_{1}^{2} + \frac{1}{2} l_{2} ω_{2}^{2}$

$K E_{f} = \frac{1}{2} (l_{1} + l_{2}) ω^{2}$

$\Rightarrow | K E_{f} - K E_{i} | = \frac{1}{2} (\frac{l_{1} l_{2}}{l_{1} + l_{2}}) {(ω_{1} - ω_{2})}^{2}$

0 0

New answer posted

11 months ago

Class 11th Work, Energy and Power

The height of Victoria falls is 63 m. What is the difference in temperature of water at the top and at the bottom of fall?

[Given 1 cal = 4.2 J and specific heat of water = 1calg^-¹ °C^-¹]

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

mgh = $m s Δ T$

$\Rightarrow Δ T = \frac{g h}{s} = \frac{10 * 63}{4200} = 0.147 ° C$

0 0

New answer posted

11 months ago

Class 11th Physics Motion in Plane

For a particle in uniform circular motion, the acceleration $\vec{a}$ at any point P(R, θ) on the circular path of radius R is (when θ is measured from the positive x-axis and v is uniform speed):

0 Follower 2 Views

Raj Pandey

Contributor-Level 9

$a = \frac{v^{2}}{R}$

$\vec{a} = - \frac{v^{2}}{R} c o s θ \hat{i} - \frac{v^{2}}{R} s i n θ \hat{j}$

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

66k Colleges
1.2k Exams
703k Reviews
1850k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Class 11th

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience