Class 11th

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

The Bond dissociation energy of D2 is greater than H2, therefore D2 reacts slower than H2.

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

U n i t o f a n 2 V 2 = a t m

U n i t o f a = a t m * u n i t o f V 2 u n i t o f n 2

= a t m * ( d m 3 ) 2 m o l 2

= atm dm6 mol-2

New answer posted

5 months ago

0 Follower 21 Views

A
alok kumar singh

Contributor-Level 10

Velocity of bob after collision,

v1 = 5 g R = 5 * 1 0 * 0 . 5 = 5 m / s

From Conservation of Momentum,

1 0 1 0 0 0 * v = 1 0 1 0 0 0 * 1 0 0 + 1 * 5  

->v = 400 m/s  

 

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Number of water molecule

Gypsum :- CaSO4.2H2O  =>          2

Plaster of paris :- CaSO4.    =>          0.5

Dead burnt plaster : CaSO4          =>          0

New answer posted

5 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Velocity of bob after collision,

v1 = 5 g R = 5 * 1 0 * 0 . 5 = 5 m / s

From Conservation of Momentum,

1 0 1 0 0 0 * v = 1 0 1 0 0 0 * 1 0 0 + 1 * 5  

->v = 400 m/s  

 

New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

λ 4 = l λ = 4 l

f = v λ = v 4 l l = v 4 f
l = 3 4 4 * 2 5 = 0 . 3 4 m = 3 4 c m

 

New answer posted

5 months ago

0 Follower 14 Views

R
Raj Pandey

Contributor-Level 9

θ = 6 0 ° 2 = 3 0 °

 

New answer posted

5 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

  T 1 4 0 0 = 3 0 0 2 4 0 T 1 = 5 0 0 K

New answer posted

5 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Time taken by first drop to reach the ground,

t 1 = 2 h g = 2 * 9 . 8 9 . 8 = 2 s              

Time for which second drop has fallen,

t 2 = t 1 t 1 2 = 2 1 2 s

Height of the second drop

= 9 . 8 1 2 * 9 . 8 * ( 2 1 2 ) 2 = 7 . 3 5 m

              

New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

( v r m s ) O 2 ( v r m s ) H 2 = M H 2 M O 2 = 2 3 2

( v r m s ) H 2 = 4 * ( v r m s ) O 2 = 4 * 1 6 0 = 6 4 0 m / s

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