Class 11th

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New answer posted

10 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

Molarity (M) = w * 1 0 0 0 m o l e c u l a r m a s s * v o l u m e o f s o l u t i o n ( m l )

= 6 . 3 * 1 0 0 0 1 2 6 * 2 5 0 = 4 2 0 = 0 . 2 M

Molecular mass of oxalic acid ( H 2 C 2 O 4 . 2 H 2 O )

= 1 * 2 + 12 * 2 + 16 * 4 + 2 * 18

              = 26 + 64 + 36 = 126

              M = 2 * 10-1 M

              = 20 * 10-2M

x * 1 0 2 = 2 0 * 1 0 2

x = 2 0

Ans. = 20

New answer posted

10 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

A 3 B 2 ( s ) ? 3 A ( a q ) + 2 + 2 B ( a q ) 3

Solubility x M 3 x M x M

K s p = [ A + 2 ] 3 [ B 3 ] 2

= ( 3 x M ) 3 ( 2 x M ) 2

= 1 0 8 ( x M ) 5

K s p = a ( x M ) 5 = 1 0 8 ( x M ) 5

Ans. a = 108

New answer posted

10 months ago

0 Follower 6 Views

R
Raj Pandey

Contributor-Level 9

(a) Torque ® ML2T-2 ↑ (iii)

(b) Impulse ® MlT-1 ↑ (i)

(c) Tension ↑ MLT-2 ↑ (iv)

(d) Surface Tension ↑  M L T 2 L = M T 2 (ii)

New answer posted

10 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

L = r * p L = m v r ( k ^ )

Direction & magnitude both remain same

 for particle moving with constant speed.

New answer posted

10 months ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

d P d V = a P , a t V = V 0 , P = P 0

Tmax =? for n = 1

d P d V = a P (Given)

On integrating, we get

P 0 P d P P = a 0 v d V

T m a x = P 0 a e R ? n = 1

New answer posted

10 months ago

0 Follower 19 Views

R
Raj Pandey

Contributor-Level 9

M V 0 = M V 1 + m V 2 . . . . ( i )

M V 1 = m V 2  . (ii)
M V 0 2 = M V 1 2 + m V 2 2 . (iii)
M V 0 2 = M V 1 2 + m ( M V 1 m ) 2 [ u s i n g e q n ( i i ) ]
( 1 + M m ) = 4
( M m ) m a x = 3

 

New answer posted

10 months ago

0 Follower 1 View

S
Syed Aquib Ur Rahman

Contributor-Level 10

The main difference lies in the direction. We should know that in a longitudinal wave, the displacement of particles is parallel to the direction of wave propagation. In a transverse wave, however, the displacement is perpendicular to the direction of wave propagation.

New answer posted

10 months ago

0 Follower 2 Views

S
Syed Aquib Ur Rahman

Contributor-Level 10

The units of angular wave number and angular frequency are slightly different.

  • Angular wave number k has units of radian per metre (rad/m).
  • Angular frequency has units of radian per second (rad/s).

 

New answer posted

10 months ago

0 Follower 4 Views

S
Syed Aquib Ur Rahman

Contributor-Level 10

In Physics, we need to know that the phase angle tells us the position of a point within one cycle of a wave. That is measured in radians. It tells you how much a wave is ahead or, behind the other. On the other hand, the initial phase (or phase constant) is the phase angle at time t=0. It tells us where the wave begins with its oscillation cycle.

New answer posted

10 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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