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7 months ago

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A
alok kumar singh

Contributor-Level 10

(a) Classical mechanics applies to the macro world and hence fails when it is applied to the micro world. In the micro world, quantum mechanics incorporates all the principles like the uncertainty principle, dual behaviour etc.

New answer posted

7 months ago

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alok kumar singh

Contributor-Level 10

(d) Rainbow is a continuous spectrum.

Assertion is a wrong statement but Reason is a correct one. Rainbow is a continuous spectrum.

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7 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Electrophiles

Nucleophiles

(iii), (iv), (v)

(i), (ii), (vi), (vii), (viii)

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

(a) For n = 4, No. of sub-shells = (l = 0, l = 1, l = 2, l = 3) = 4.

(b) Total number of orbitals which can be present = n2 = 42 = 16.
Each orbital can have an electron with ms = – 1/2. Total no. of electrons with m, = – 1/2 is 16.

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7 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

In presence of (Ph-CO-O)2it lead to CH3-CH2-CH2Br as the reaction undergo by free radical mechanism

However in absence of (Ph-CO-O)2 the reaction undergo by carbocation intermediate thus lead to give CH3-CHBr-CH3

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7 months ago

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alok kumar singh

Contributor-Level 10

(a) P (Z=15) : [Ne]103s23p3  No. of unpaired electrons = 3
(b) Si (Z=14) : [Ne]103s23p2  No. of unpaired electrons = 2
(c) Cr (Z=24): [Ar]184s13d5  No. of unpaired electrons = 6
(d) Fe (Z=26): [Ar]184s23d6  No. of unpaired electrons = 4
(e) Kr (Z=36) : [Ar]184s23d104p6  No. of unpaired electrons = Nil.

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

Configuration of the two elements are:

Al (Z = 13): [Ne]103s23p1

Si (Z = 14): [Ne]103s23p2
The unpaired electrons in silicon (Si) will experience more effective nuclear charge because the atomic number of the element Si is more than that of Al.

New answer posted

7 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

New answer posted

7 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

Greater the penetration of the electron present in a particular orbital towards the nucleus more will be the magnitude of the effective nuclear charge. Based upon this

(i) 2s orbital is closer to the nucleus than 3s orbital and hence it will experience more effective nuclear charge.

(ii) 4d orbital will experience more effective nuclear charge due to its closer proximity to 4f orbital.

(iii) 3p orbital will experience more effective nuclear charge as it is closer to the nucleus

New answer posted

7 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The nitro group strongly deactivate the benzene towards the electrophilic substitution reaction due to the -R and -I effect

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