Class 11th

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New answer posted

6 months ago

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V
Vishal Baghel

Contributor-Level 10

Lower the electrode potential, better is the reducing agent. Since the electrode potentials increase in the order: K+/K (-2.93 V), Mg2+/Mg (-2.37 V), Cr3+/Cr (-0.74 V), Hg2+/Hg (0.79 V), Ag+/Ag (0.80 V), therefore, reducing power of metals decreases in the same order, i.e., K, Mg, Cr, Hg, Ag.

New answer posted

6 months ago

0 Follower 25 Views

V
Vishal Baghel

Contributor-Level 10

Based on the relative positions of these metals in the activity series, the correct order is Mg, Al, Zn, Fe, Cu.

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

5.36.  Avogadro law states that equal volumes of all gases under same conditions of temperature and pressure contain equal number of molecules.

Dalton's law of partial pressure states that total pressure exerted by a mixture of non-reacting gases is equal to the sum of partial pressures exerted by them.

Boyle's law states that under isothermal condition, pressure of a fixed amount of a gas is inversely proportional to its volume.

Charles' law is a relationship between volume and absolute temperature under isobaric condition. Itstates that volume of a fixed amount of gas is directly proportional to its absolute temperature (V? T)

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New answer posted

6 months ago

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V
Vishal Baghel

Contributor-Level 10

(i) An aqueous solution of AgNO3?  with silver electrodes.
At cathode: Silver ions have lower discharge potential than hydrogen ions. Hence, silver ions will be deposited in preference to hydrogen ions.

At anode: Silver anode will dissolve to form silver ions in the solution.
Ag → Ag+ + e

(ii) An aqueous solution of AgNO3?  with platinum electrodes.

At cathode: Silver ions have lower discharge potential than hydrogen ions. Hence, silver ions will be deposited in preference to hydrogen ions.

At anode: Hydroxide ions having lower discharge potential will be discharged in preference to nitrate ions. Hydroxide ions wil

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New answer posted

6 months ago

0 Follower 33 Views

V
Vishal Baghel

Contributor-Level 10

(i) When emf is positive, the reaction is feasible.
Eo? cell = Eo? Fe? −Eo? I2? =0.77−0.54=0.23V
Reaction is feasible.


(ii) Eo? cell? =Eo? Ag? −Eo? Cu? =0.80−0.34=0.46V
Reaction is feasible.


(iii) Eo? cell? =Eo? Fe? −Eo? Cu? =0.77−0.34 =0.43 V
Reaction is feasible.


(iv) Eo? cell? =Eo? Fe? −Eo? Ag? =0.77−0.80=−0.03 V
Reaction is not feasible.


(v) Eo? cell? =Eo? Br2? ? −EFe? =1.09−0.77=0.32 V 
Reaction is feasible.

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

5.35. When density of liquid and vapours becomes the same; the clear boundary between liquid and vapours disappears. This temperature is called critical temperature.

New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

The balanced equation for the reaction is:

4NH3? (g)+5O2? (g)→4NO (g)+6H2? O (g)

The molar masses of ammonia and oxygen are 17 g/mol and 32 g/mol respectively.

68 g of NH3 will react with O2 = 160 g.

Therefore, 10 g of NH3 will react with O2 = 160/68 x 10 g = 23.6 g
But the amount of O2 which is actually available is 20.0 g which is less than the amount which is needed. Therefore, O2 is the limiting reagent and hence calculations must be based upon the amount of O2 taken and not on the amount of NH3 taken. From the equation,
160 g of O2 produce NO = 120 g
Therefore, 20 g of O2 will produce NO =120/160 x 20 = 15 g

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

5.34. The temperature at which the vapour pressure of a liquid is equal to external pressure is called boiling point of liquid.

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

5.33. Molecules of liquids are held together byattractive intermolecular forces. Liquids havedefinite volume because molecules do notseparate from each other. However, moleculesof liquids can move past one another freely, therefore, liquids can flow, can be poured andcan assume the shape of the container in whichthese are stored.

New answer posted

6 months ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

(a) Phosphorous, chlorine and sulphur are the non metals which can show disproportionation reaction. The reactions shown are:

P4? + 3OH? + 3H2? O? PH3? + 3H2? PO2?

? Cl2? + 2OH? ? Cl? + ClO? + H2? O

S8? +12OH? ?4S2? +2S2? O32? ? +6H2? O

 

(b) Copper, gallium and indium are the metals that show disproportionation reaction. 

The reactions are shown below.

2Cu+? Cu2+ + Cu

3Ga+? Ga3+ + 2Ga

3In+? In3+ + 2In

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