Class 12th

Get insights from 12k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
12k

Questions

0

Discussions

28

Active Users

0

Followers

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

n (7800) = (n + 1) 5200

New answer posted

a year ago

0 Follower 17 Views

A
alok kumar singh

Contributor-Level 10

  I = 1 2 − 0 . 3 5 * 1 0 3 = 2 . 3 4 m A

V 0 = I R = ( 2 . 3 4 * 1 1 − 3 ) ( 5 * 1 0 3 ) = 1 1 . 7 V  

            

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

v? = 2î F? = -2?
v? = 2? F? = -2î
⇒ B? is along -k? Hence v? = 2k? ⇒ F? = 0

New answer posted

a year ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Gain in K.E. =  Loss in P.E.

  K p = e V for proton

K α = 2 e V  for  α - particle

Again, Loss in K.E. =   Work against field

K p = e E ⋅ S 0  for proton

⇒ e V = e E S 0

∴ S 0 = V E

K α = 2 e E . S  for α -  particle

⇒ 2 e V = 2 e E S

∴ S = V E = S 0

New answer posted

a year ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

tan 60° = (2kλ? /y? )/ (2kλ? /x? )


(√3λ? /x? ) = (λ? /y? ); √3λ? y? = λ? x?

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

  e A s u n σ T 4 4 π r 2 * A p r o j     E a r t h
4 π R 2 4 π r 2 σ T 4 π r 0 2
π R 2 r 2 r 0 2 σ T 4

            

            

New answer posted

a year ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

d = Rsin 60°


⇒ d = (mv√3)/ (qB 2) = (√3v)/ (2aB)

New answer posted

a year ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

E =   Energy     time   *   Area   ⇒ [ E ] = [   Energy   ] [   time   ] [   Area   ] = M L 2 T - 2 L 2 T

[ E ] = M L 0 T - 3

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

  I = E R 2

U I n d u c t o r = H e a t     l o s s     i n     R 1 = 1 2 L ( E R 2 ) 2              

New answer posted

a year ago

0 Follower 36 Views

A
alok kumar singh

Contributor-Level 10

The time period of LC oscillations,

  T = 2 π L C          

The time at which charge on the capacitor will be zero is  T 4 .  

So t    = π 2 L C

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 67k Colleges
  • 1.2k Exams
  • 716k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.