Class 12th
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New answer posted
2 months ago
Contributor-Level 10
V = ir
i = V/r
i = (1/r) [v is same for r? & r? ]
i? /i? = r? /r?
i? = (r? / (r? +r? )i?
i? /i? = r? / (r? +r? )
New answer posted
2 months agoContributor-Level 10
Total case = ¹? C?
Favourable cases
? C? (Select x? )
³C? (Select x? )
? C? (Select x? )
P = (6.3.7)/¹? C? = 1/68
New answer posted
2 months agoContributor-Level 10
a = I + j – k
c = 2i – 3j + 2k
Now,
b x c = a
=> (i+j–k) (2i–3j+2k) = 0
=> 2 – 3 – 2 = 0
=> –3 = 0 (Not possible)
=> No possible value of b is possible.
New answer posted
2 months agoContributor-Level 10
p = nhc/λ ⇒ n = pλ/hc
n = (3.3 * 10? ³ * 600 * 10? ) / (6.6 * 10? ³? * 3 * 10? ) = 10¹?
New answer posted
2 months agoContributor-Level 10
l + m – n = 0 => n = l + m
3l² + m² + cnl = 0
3l² + m² + cl (l+m) = 0
= (3+c) (l/m)² + c (l/m) + 1 = 0
? Lines are parallel
D = 0
c = 4 (as c > 0)
New answer posted
2 months agoContributor-Level 10
dy/dx + (2? (2? -1)/ (2? ¹ (2? -1) = 0
x, y > 0, y (1) = 1
dy/dx = – (2? (2? -1)/ (2? (2? -1)
∫ (2? -1)/2? dy = –∫ (2? -1)/2? dx
log? (2? -1)/log?2 = – log? (2? -1)/log?2 + log? c/log?2
Taking log of base 2.
∴ y = 2 – log?3
New answer posted
2 months agoContributor-Level 10
I = ∫? ² (x³+|x|)/ (e|x|+1) dx . (i)
I = ∫? ² (x³+|x|)/ (e? |x|+1) dx . (ii)
= ∫? ² |x| dx = 2∫? ² x dx
= [x²/2]? ² = (16/4 + 4/2) - 0
= 4+2=6
New answer posted
2 months agoContributor-Level 10
I = ∫ (e? (x²+1)/ (x+1)² dx = f (x)e? + c
I = ∫ (e? (x²-1+1+1)/ (x+1)² dx
I = ∫e? [ (x-1)/ (x+1) + 2/ (x+1)² ] dx
for x = 1
f' (1) = 12/24 - 12/16 = 3/4
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