Class 12th

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New answer posted

2 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Is? = 4I?
Is? = I?
∴ I_max/I_min = (√Is? + √Is? )² / (√Is? - √Is? )² = (2+1)²/ (2-1)² = 9/1

New answer posted

2 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

N = [n + n/10 + n/100 + .]
= n/ (1 - 1/10) = 10/9

New answer posted

2 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

2 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

OH group is the more activating group and ortho-para director, hence ortho position attach will provide meta substituted product with respect to – CH3 in option (C).

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

i = 60? , μ = √3
∴ 1 * sin (60? ) = √3 * sin r
=> r = 30?
∴ angle with x-axis = 60?

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?

New answer posted

2 months ago

0 Follower 1 View

S
Sejal Baveja

Contributor-Level 10

Yes, candidates can get admission in CEM- College of Engineering & Management, Kolaghat with 60% in Class 12. The minimum required aggregate for the same is 45% (40% in the case of reserved category). Candidates must appear for the JEE Main or WBJEE exam to take admission in the BTech course at CEM- College of Engineering & Management, Kolaghat. 

New answer posted

2 months ago

0 Follower 53 Views

V
Vishal Baghel

Contributor-Level 10

1/f_lens = (1.5/ (4/3) - 1) ( - 2/15) = f_lens = -60cm
∴ 1/fe = 2/ (-60) + 2/ (-15) => fe = -6 cm
∴ V = (14 * (-6)/ (14 + 6) = 4.2 cm from lens (virtual)

New answer posted

2 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

sin 60? = AP/ (lcos (30? )
AP = 3l/4

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

i = (V? /R) (1 - e? /? )
U = ½Li²
dU/dt = Li (di/dt)
(R/2L) * (V? ²/R²) (1 - e? /? )²e? /? = (V? ²/R) (1 - e? /? )
t = (L/R)ln2

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