Class 12th

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New answer posted

a year ago

0 Follower 32 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a year ago

0 Follower 5 Views

P
Pallavi Arora

Beginner-Level 5

The direction of the net magnetic force is always perpendicular to the plane of current-carrying conductors. The direction of the magnetic force is determined through the right-hand rule. 

The right-hand thumb rule states that if you wrap a wire in a way that the thumb points towards the flow of current. Then your curled fingers represent the direction of the field lines of the magnetic field

New answer posted

a year ago

0 Follower 2 Views

A
Anushree Tiwari

Beginner-Level 5

The "ampere" was defined based on the magnetic interaction. The scientific community used the magnetic force between two parallel current-carrying conductors placed at a distance. Below is the definition of 1 ampere, based on this concept.

1 Ampere is the constant current that produces a magnetic force of exactly  2*10? 7? N/m, when two infinitely long, straight, parallel conductors are placed one meter apart in vacuum.

New answer posted

a year ago

0 Follower 1 View

C
Chandra Pruthi

Beginner-Level 5

The exact formula for the magnetic force per unit length between two parallel current-carrying conductors:

F l = ? 0 I1 I2 2? d For more information, check: Force between parallel conductors

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

3 [Co (en)? Cl? ]Cl + 3AgNO? (excess) → 3AgCl↓ (ppt) + 3 [Co (en)? Cl? ] NO?
Secondary valency of complex = 6

New answer posted

a year ago

0 Follower 16 Views

A
alok kumar singh

Contributor-Level 10

E_cell = E? _cell - (0.059/2)log { [Cu²? ]/ [Ag? ]²}
E? = E? _cell - (0.059/2)log [0.1/ (0.01)²] = 0.3095
E? _cell = 0.3095 + 0.0885 V
E? _cell = 0.398

Again, E? = E? _cell - (0.059/2)log [10? ²/ (10? ³)²]
E? = 0.398 - (0.059/2) x 4 V

E? = 0.28 V
E? = 28 x 10? ² V

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

1.     The number of chiral carbons in open-chain aldohexose (such as glucose) is four, therefore, the number of stereoisomers? 2? 16.

New answer posted

a year ago

0 Follower 15 Views

A
alok kumar singh

Contributor-Level 10

2SO? (g) + O? (g)? 2SO? (g)
t=0: 250 m bar 750 m bar -
0 625 m bar 2 x 250 = 500
P_total = 625 + 250m bar
= 875mbar

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

ATP has phosphate group, PO? ³?
So x + 4 (-2) = - 3 or x = + 5

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