Class 12th

Contributor-Level 10

p²/2m = Vq => p = √2mVq
θ = sin? ¹ (l/R') = l/R = mV/qB = p/qB

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a year ago

A multi range current ammeter can be constructed by using a galvanometer circuit as shown in figure. We want a current meter that can measure 10 mA, 100 mA and 1A using a galvanometer of resistance 10 Ω and that produces maximum deflection for current 1 mA. Value of S₁ + S₂ + S₃ in ohms is

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Class 12th Physics Ncert Solutions Class 12th

Contributor-Level 10

IgRc = (I - Ig) (S? + S? + S? )
1mA * 10 = 9mA (S? + S? + S? )

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a year ago

For the following logic circuit, the truth table is:

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Contributor-Level 9

Kindly consider the following Image

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a year ago

A dielectric slab of dielectric constants k is slowly inserted inside the parallel plate capacitor having plate area A and separation between plates d as shown in figure. If dimensions of dielectric slab is same as plates of capacitor and capacitor is connected through the battery, then work done by agent will be (C = ε₀ A/d)

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Contributor-Level 10

W_agent + W_battery = ΔU
W = ½ (KC - C)V² - [ (KC - C)V]V
= ½ (K - 1)CV²

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a year ago

The radius of inner most orbit of hydrogen atom is $5.3 * 10^{- 11} m$ . What is the radius of third allowed orbit of hydrogen atom?

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Contributor-Level 9

$r_{n} = a_{0} n_{2}$

$\begin{array}{r} r_{1} = a_{0} = 5.3 * 10^{- 11} m \\ r_{3} = a_{0} (3) 2 \\ = 5.3 * 10^{- 11} * 9 \\ = 4.77 ? \end{array}$

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a year ago

A short dipole of dipole moment P is placed along x – axis at a distance d from a long wire having uniform linear charge density +λ (wire is along y – axis) as shown. Find minimum work required to align this dipole along y axis (so that dipole moment P is along +y direction)

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Class 12th Physics Ray Optics and Optical Instruments

Contributor-Level 10

W = Uf - Ui
= 0 - (-P (λ/2πε? d)
= Pλ/2πε? d

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a year ago

Two thin lenses are of same focal lengths (f), but one is convex and the other one is concave. When they are placed in contact with each other, the equivalent focal length of the combination will be:

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Class 12th Physics Ray Optics and Optical Instruments

Contributor-Level 9

$F_{convex} = f$

$F_{concave} = - f$

$\begin{array}{r} \frac{1}{f_{comb}} = \frac{1}{F_{convex}} + \frac{1}{F_{concave}} \\ = \frac{1}{f} - \frac{1}{f} \end{array}$

$\Rightarrow f_{comb} = \infty$

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a year ago

In the figure shown here, what is the equivalent focal length of the combination of lenses (Assume that all layers are thin)?

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Contributor-Level 9

$\frac{1}{f_{1}} = (1.6 - 1) (\frac{1}{\infty} - \frac{1}{20}) = - \frac{3}{100}$

$\frac{1}{f_{2}} = (1.5 - 1) (\frac{1}{20} - \frac{1}{- 20})$ $= \frac{1}{20}$

$\frac{1}{f_{3}} = \frac{1}{f_{1}} = - \frac{3}{100}$

$\frac{1}{f_{net}} = \frac{1}{f_{1}} + \frac{1}{f_{2}} + \frac{1}{f_{3}}$

$= - \frac{3}{50} + \frac{1}{20}$

$\Rightarrow f_{n e t} = - 100 c m$

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a year ago

A series LCR circuit containing 5.0H inductor, 80μF capacitor and 40Ω resistor is connected to 230 V variable frequency ac source. The angular frequencies of the source at which power transferred to the circuit is half the power at the resonant angular frequency are likely to be:

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alok kumar singh

Contributor-Level 10

Q = ω? L/R ⇒ Δω = R/L = 50/4 = 8rad/sec
Δω
ω? = 1/√LC = 1/√ (5*80*10? ) = 50rad/sec
ω? = ω? - Δω/2 = 46rad/sec
ω? = ω? + Δω/2 = 54rad/sec

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a year ago

The net impedance of circuit (as shown in figure) will be:

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