Class 12th

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

Aspirin and paracetamol belongs to the class of non-narcotic analgesic.
Morphine and heroin are narcotic analgesics.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

In the presence of peroxide, addition of HBr to unsymmetrical alkenes take place by anti-Markovnikov's rule/Peroxide effect/Kharash effect.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

π = iCRT
P? = 1 * (10/180) * R * T (For Glucose)
P? = 1 * (10/60) * R * T (For Urea)
P? = 1 * (10/342) * R * T (For Sucrose)

∴ P? > P? > P?

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

10amines react with Hingsberg's reagent to give a solid, which dissolve in alkali.

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

Λ°m (NaCl) = 126.45Scm² mol? ¹
Λ°m (HCl) = 426.16Scm² mol? ¹
Λ°m (CH? COONa) = 91Scm² mol? ¹
Λ°m (CH? COOH) =Λ°m (CH? COONa) +Λ°m (HCl)−Λ°m (NaCl)
= 91 + 426.16 – 126.45
= 391.72Scm² mol? ¹

New question posted

2 months ago

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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Vitamin B? deficiency → Pernicious anaemia (RBC deficient in heamoglobin)

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2 months ago

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R
Raj Pandey

Contributor-Level 9

| τ ? | = P E s i n ? θ 4 = q * 2 a * E s i n ? 30 ?

q = 4 2 * 10 - 2 * 2 * 10 5 * 1 2

= 2 * 10 - 3 C

= 2 m C

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

Fundamental harmonic frequency open pipe

= V 2 L = v 1

(say)

Fundamental harmonic frequency of closed pipe = V 4 L

= v 2 (say)

v 1 v 2 = V 2 L V 4 L 2 : 1

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Diameter = main scale reading + (circular scale reading * least count)
Diameter = 0 + (52 * 0.01 mm) = 0.52 mm = 0.052 cm.
In the RLC circuit:
Given I? = 10√2 A, so I? = I? /√2 = 10 A.
V? = √ [V? ² + (V? - V? )²] = √ [40² + (40 - 10)²] = √ [1600 + 30²] = √ [1600 + 900] = √2500 = 50 V.
Impedance Z = V? / I? = 50 V / 10 A = 5 Ω.
For Hindi: I? = 10√2 A, V? = 50V, Z = V? /I? = 50/ (10√2) = 5/√2 Ω.

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