Class 12th

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3 months ago

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New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Oxidation state in neutral medium changes from +7 to +4 for MnO? to MnO?

New answer posted

3 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

In n-type semiconductor majority charge carriers are e- and P type semiconductor majority charge carriers are holes.

I = n e A V d = neA ( μ E )

μ e > μ h I e > I h

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Ecell = 1.05 - (0.059 / 2) log ( [Ni²? ] / [Ag? ]²)
= 1.05 - (0.059 / 2) log ( [10? ³] / [10? ³]²)
= 1.05 - (0.059 * 3) / 2 = 1.05 - 0.0885 = 0.9615 volt
There is a misprint in the question. The E? cell is incorrectly given as 10.5 V. This should have been 1.05 volt.

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Statement I is true but statement II is incorrect as 3°-alcohols are the most reactive and give immediate turbidity with Luca's reagent.

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Hematite: Fe? O?
Magnetite: Fe? O?
Calamine: ZnCO?
Kaolinite: [Al? (OH)? Si? O? ]

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

kc = [O? ]² / [O? ]³
3 * 10? = [O? ]² / [4 * 10? ²]³
[O? ]² = 192 * 10? ⇒ [O? ] = 4.38 * 10? ³²

New answer posted

3 months ago

0 Follower 6 Views

R
Raj Pandey

Contributor-Level 9

Gravitational constant = M - 1 L 3 T - 2

Gravitational potential energy = M L 2 T - 2

Gravitational potential = L 2 T - 2

Gravitational intensity = L T - 2

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

k = (2.303 / 5) log (0.1 / 0.001) = (2.303 * 2) / 5 = 4.606 / 5 = 0.921 min? ¹

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