Class 12th
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New answer posted
3 months agoContributor-Level 10
The greater stability of Cu²? (aq) rather than Cu? (aq) is due to the much more negative ΔhydH of Cu²? (aq) than Cu? , which more than compensates for the second ionisation enthalpy of Cu.
New answer posted
3 months agoContributor-Level 10
BF? behaves as Lewis acid due to incomplete octet in valence shell of Boron. Hence it can accept a lone pair of electrons.
New answer posted
3 months agoContributor-Level 10
When the reactants and the catalyst are in different phases, then the catalysis is known as heterogenous catalysis.
1. N? (g) + 3H? (g) - (Fe (s)-> 2NH? (g) (Heterogenous catalysis)
2. 2SO? (g) + O? (g) - (NO (g)-> 2SO? (g) (Homogenous catalysis)
3. C? H? O? (aq) + H? O (l) → C? H? O? (aq) + C? H? O? (aq) (Homogenous catalysis)
4. NO (g) + O? (g) → NO? (g) + O? (g)
New answer posted
3 months agoContributor-Level 10
A reaction can have zero activation energy, for example, •CH? + •CH? → CH? − CH? has zero activation energy.
New answer posted
3 months agoContributor-Level 10
Let the new rate be, R'.
A' = [3 A], B' = [B]
R' = K [A']² [ B']
= K [3 A]² [ B]
= 9 K [ A]² [ B]
= 9 * R
Hence, rate would become nine times.
New answer posted
3 months agoContributor-Level 10
Free energy is extensive property, and E°cell is an intensive property. ΔrG is depends on the ' n ' which is number of electron transferred in the reaction ΔrG = −nFE°
New answer posted
3 months agoContributor-Level 10
Conductivity = Conductance * Cell constant
Conductivity = (1/ resistance )
Cell constant = Conductivity * Resistance
Cell constant = 0.0210 * 60 = 1.26Cm? ¹
New answer posted
3 months agoContributor-Level 10
Since, atom B forms CCP structure. Therefore, there will be 4-B atoms.
Now, atom A occupies 1/3 of tetrahedral voids.
Hence, number of A atoms = 1/3 * 8 = 8/3
The correct formula of the compound = A? /? B?
= A? B?
x + y = 2 + 3 = 5
New answer posted
3 months agoContributor-Level 10
H? O < H? S < H? Se < H? Te
Down the group acidic strength increases
So pK? value decreases
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