Class 12th
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New answer posted
a year agoContributor-Level 9
OH group is the more activating group and ortho-para director, hence ortho position attach will provide meta substituted product with respect to – CH3 in option (C).
New answer posted
a year agoContributor-Level 10
i = 60? , μ = √3
∴ 1 * sin (60? ) = √3 * sin r
=> r = 30?
∴ angle with x-axis = 60?
New answer posted
a year agoContributor-Level 10
M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?
New answer posted
a year agoContributor-Level 10
Yes, candidates can get admission in CEM- College of Engineering & Management, Kolaghat with 60% in Class 12. The minimum required aggregate for the same is 45% (40% in the case of reserved category). Candidates must appear for the JEE Main or WBJEE exam to take admission in the BTech course at CEM- College of Engineering & Management, Kolaghat.
New answer posted
a year agoContributor-Level 10
1/f_lens = (1.5/ (4/3) - 1) ( - 2/15) = f_lens = -60cm
∴ 1/fe = 2/ (-60) + 2/ (-15) => fe = -6 cm
∴ V = (14 * (-6)/ (14 + 6) = 4.2 cm from lens (virtual)
New answer posted
a year agoContributor-Level 10
i = (V? /R) (1 - e? /? )
U = ½Li²
dU/dt = Li (di/dt)
(R/2L) * (V? ²/R²) (1 - e? /? )²e? /? = (V? ²/R) (1 - e? /? )
t = (L/R)ln2
New answer posted
a year agoContributor-Level 10
(4/3)πR³ = 27 (4/3)πr³) ⇒ R = 3r (i)
v = Kq/r = V? /r = (q? /q? ) (r? /r? ) (i)
⇒ 220/V? = (q/ (27q) (3r/r) (i)
⇒ 220/V? = 1/9 (i)
⇒ V? = 220 * 9 = 1980 volt (i)
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