Class 12th

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New answer posted

10 months ago

0 Follower 15 Views

A
alok kumar singh

Contributor-Level 10

R = 100Ω. tanφ = (X_L-X_C)/R. tan45° = X_L/R (since it's an inductor). X_L=R=100Ω.
Lω=100 ⇒ L (2πf)=100 ⇒ L = 100/ (2π1000) ≈ 1.59 * 10? ² H. The closest option is (A).

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

l = 10 * pitch = 10 * (2πmvcosθ/qB)
= 20π * 1.67*10? ²? * 4*10? * (1/2) / (1.6*10? ¹? * 0.3) = 0.44 m

New answer posted

10 months ago

0 Follower 31 Views

A
alok kumar singh

Contributor-Level 10

Δl = lαΔT ⇒ Δl/l = αΔT = 0.02%
Δρ = -ργΔT
|Δρ/ρ| = γΔT = 3αΔT = 3 (0.02%) = 0.06%

New answer posted

10 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

 2θ = 60° ⇒ θ = 30°
h = 2Tcosθ / (ρsg) = 2 (0.05)cos30° / (667) (0.15 * 10? ³) (10) = (√3 * 100)/ (667 * 3) ≈ 173.2/2000 m = 8.66 cm

New answer posted

10 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

10 months ago

0 Follower 12 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Angular width of a fringe is YDSE

 

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

10 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

The law of radioactive decay is N = N? e? λt, where N is the amount remaining at time t.
Given that at time t, N/N? = 9/16.
So, 9/16 = e? λt
At time t/2, the fraction remaining will be N'/N?
N' = N? e? λ ( t/2 ) = N? (e? λt)¹/²
Substituting the value of e? λt:
N' = N? (9/16)¹/² = N? (3/4)
The fraction remaining is N'/N? = 3/4.

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