Class 12th

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New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

[Ni (NH? )? Cl? ] is square planar and tetrahedral. It doesn't show isomerism.

 

 

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

HI cleavage of ether. B is CH? =CHI, gives yellow PPT with AgNO? C is C? H? CH? OH.

 

 

 

New answer posted

7 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Normal to plane is n= (-4i+5j+7k).
Plane: -4 (x-3)+5 (y-1)+7 (z-1)=0 ⇒ -4x+5y+7z=0.
Passes through (α, -3,5) ⇒ -4α-15+35=0 ⇒ α=5.

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

(a) is true, (b) is true.

New answer posted

7 months ago

0 Follower 20 Views

A
alok kumar singh

Contributor-Level 10

Acidity: b (carboxylic acid)>c (phenol)>d (enol)>a (alkyne).

New answer posted

7 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

A? A = I
⇒ a²+b²+c²=1 and ab+bc+ca=0
Now, (a+b+c)²=1 ⇒ a+b+c=±1
So, a³+b³+c³-3abc = (a+b+c) (a²+b²+c²-ab-bc-ca) = (±1) (1-0)=±1
⇒ 3abc = 2±1 = 3,1
⇒ abc = 1, 1/3

New answer posted

7 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

This is electrophilic substitution reaction which is determine by electronic effect of

 

 

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

From I&II, rate∝ [B]². From I&III, rate∝ [A]¹.
From IV: 7.2e-2 = k (X) (0.2)². From II: 2.4e-2=k (0.1) (0.2)². X=0.3.
From V: 2.88e-1=k (0.3) (Y)². k=2.4e-2/ (0.1*0.04)=6.
2.88e-1 = 6 (0.3)Y². Y²=0.16. Y=0.4.

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Cast iron is used to make wrought iron and steel.

New answer posted

7 months ago

0 Follower 16 Views

A
alok kumar singh

Contributor-Level 10

E2 elimination. Most acidic proton is removed. Fluorine is more electronegative.

 

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