Class 12th
Get insights from 11.9k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
7 months agoContributor-Level 10
At lower end
Tension, T? = 2g = 20 N (due to the 2 kg block)
Velocity, v? = √ (T? /μ) = √ (20/μ)
Wavelength, λ? = 6 cm
At upper end
Tension, T? = (2 kg + 6 kg)g = 8g = 80 N (due to the block and the rope)
Velocity, v? = √ (T? /μ) = √ (80/μ) = √4 * √ (20/μ) = 2v?
Since frequency (f) remains the same:
f = v? /λ? = v? /λ?
⇒ λ? = λ? * (v? /v? )
⇒ λ? = λ? * (2v? /v? ) = 2λ?
⇒ λ? = 2 * 6 cm = 12 cm
New answer posted
7 months agoIf A = {X = (x,y,z)?: PX=0 and x²+y²+z²=1}, where P = [1, 2, 1; -2, 3, -4; 1, 9, -1], then the set A
New answer posted
7 months agoContributor-Level 9
f' (x)= (x- (1+x)ln (1+x)/ (x² (1+x). Let h (x)=x- (1+x)ln (1+x).
h' (x)=-ln (1+x). h' (x)>0 for x∈ (-1,0), <0 for x (0, ).
h (0)=0, so h (x)≤0. f' (x)≤0. f is decreasing.
New answer posted
7 months agoContributor-Level 10
E°_cell = E° (cathode)-E° (anode) = 0.16-0.52=-0.36V.
lnK = nFE°/RT = 1*0.36/0.025 = 14.4. Ans is x10? ¹, so 144.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers







