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New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

  Phase |            Medium |          Colloid Type |
| (1) Cheese |            liquid | solid |    Gel |
| (2) Pumice stone |  gas | solid |        Solid sol |
| (3) Hair cream |      liquid | liquid |    Emulsion |
| (4) Cloud | liquid |  gas | Aerosol |

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Chelation increases stability of complex. Also more the chelation more the stability. Here, [Co (en)? (NH? )? ]Cl? , [Co (en)? ]Cl? and [Co (en) (NH? )? ]Cl? have chelation due to ethylenediamine. Therefore [Co (en)? ]Cl? has the highest chelation so the highest stability.

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

Using, µ = √n (n+2) B.M, n = number of unpaired electrons.
? Ti? ³ = 4s? 3d¹, unpaired electron = 1
µ = 1.73 B.M
? V? ² = 4s? 3d³, unpaired electron = 3
µ = 3.87 B.M
? Sc? ³ = 4s? 3d? , unpaired electron = 0
µ = 0 B.M

New answer posted

10 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

Heating of cis-but-2-enedioic acid gives maleic anhydride as shown.
[Chemical reaction showing conversion of cis-but-2-enedioic acid to maleic anhydride upon heating]

 

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

A = A? (1/2)?
A/A? = 1/8 = (1/2)³ ⇒ n = 3
t = n T½
30 = 3 T½
T½ = 10 years

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

ni² = ne * nh
(1.5*10¹? )² = ne * (4.5*10²²)
ne = (2.25 * 10³²)/ (4.5 * 10²²) = 0.5 * 10¹? = 5 * 10? / m³

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Mean free path:
λ ∝ 1/ (nd²)
λA/λB = (d_B²/d_A²) = (5²/10²) = 25/100 = 25 * 10? ²

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Modulation Index
μ = Am/Ac = 20/20 = 1

New answer posted

10 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

K = hc/λ - W?
K = (20*10? ²? )/ (500*10? ) - 1.25 * 1.6*10? ¹?
K = 4*10? ¹? - 2*10? ¹? = 2*10? ¹? J
R = √ (2mK)/ (eB)
B = √ (2mK)/ (eR) = √ (2 * 9*10? ³¹ * 2*10? ¹? ) / (1.6*10? ¹? * 30*10? ²)
B = √ (36*10? ) / (48*10? ²¹) = (6*10? ²? ) / (4.8*10? ²? ) = 1.25 * 10? T
B = 125 * 10? T

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Power dissipated is same
P? = P?
P_R = P_RLC
(V²/R) = (V²/Z)cos (φ) = (V²/Z) (R/Z) = V²R/Z²
R = R²/Z² => Z² = R²
R² + (ωL - 1/ωC)² = R²
ωL = 1/ωC
ω = 1/√ (LC) = 1/√ (0.1 * 40 * 10? ) = 1/√ (4 * 10? ) = 1/ (2 * 10? ³) = 500 rad/s

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