Class 12th

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New answer posted

7 months ago

0 Follower 24 Views

A
alok kumar singh

Contributor-Level 10

Enet = Eo/k
Enet = E_free - E_bound = qf/Aε? - qb/Aε?
Eo = qf/Aε?
So, (qf-qb)/Aε? = qf/ (kAε? )
qf - qb = qf/k
qb = qf (1 - 1/k)

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Given 2q? = q? and v? /v? = 2/3, m? = m?
r = mv/qB
r? /r? = (m? /m? ) * (v? /v? ) * (q? /q? )
r? /r? = (1) * (2/3) * (2) = 4/3

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

μ = sin (A + δm)/2) / sin (A/2)
Since, δm = A
μ = sin (A) / sin (A/2) = (2sin (A/2)cos (A/2) / sin (A/2)
μ = 2cos (A/2

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

I = I? cosωt
Current is changing from its maximum value to rms value (I? /√2)
I? /√2 = I? cosωt
cosωt = 1/√2
ωt = π/4
2π * 50t = π/4
t = 1/400 s = 2.5 ms

New answer posted

7 months ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

tan 37° = E? /E?
E? = k (2p? /r³) axial direction
E? = k (p? /r³) equatorial direction
tan 37° = (k p? /r³) / (k 2p? /r³) = p? / (2p? ) = 3/4
p? /p? = 2/3

 

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

For electron,
λe = h/p ⇒ (KE)e = ½mv² = p²/ (2m) = (h²/λ²)/ (2m)
For photon,
λp = h/p ⇒ (K.E.)p = pc = hc/λ
KEe / KEp = (h²/ (2mλ²) / (hc/λ) = h/ (2mcλ)
But for electron p = mv = h/λ so h/λ = mv
KEe / KEp = mv / (2mc) = v/2c

New answer posted

7 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

ε? = 250 * Potential Gradient
ε? + ε? = 400 * Potential Gradient
(ε? )/ (ε? + ε? ) = 250/400 = 5/8
By solving above
ε? /ε? = 5/3

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

By shell's law
(sin θ)/ (sin θ') = 4/3 . (i)
For TIR on second surface
sin θ' > sin θc
(θ' + θ' = 90)
sin (90 - θ') > sin θc
cos θ' > sin θc
1 - sin²θ' > sin²θc (By equation (i) )
1 - (3/4 sin θ)² > sin²θc
[sin θc = 3/4]
1 - (9/16)sin²θ > (9/16)
1 - 9/16 > (9/16)sin²θ
7/16 > (9/16)sin²θ
sinθ < 7/3

New answer posted

7 months ago

0 Follower 2 Views

V
Virajita Arora

Contributor-Level 10

Yes, Institute of Hotel Management Studies, Kotdwar accept Class 12th marks. Candidates seeking admission to all programmes can enrol for admission with Class 12 marks. The college offers Certificate and Diploma courses. Institute of Hotel Management Studies, Kotdwar admissions are based on merit.

New answer posted

7 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

λ = h/mv = h/√2mK
For same K:
λ ∝ 1/√m
λ? : λ? : λ? = 1/√m? : 1/√m? : 1/√4m?
As m? > m? ,
λ? > λ? > λ?

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