Class 12th
Get insights from 11.9k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
10 months agoContributor-Level 10
C = 200µF, R
Q/A = constant [Given]
A = A? e? & Q = Q? e? /?
Q/A = (Q? /A? ) e^ (-t/RC + λt) = constant
For this to be constant, the exponent must be zero.
-t/RC + λt = 0
1/RC = λ
R = 1/ (λC) =
New answer posted
10 months agoContributor-Level 10
r = 0.5Å = 0.5*10? ¹? m
v = 2.2*10? m/s
I =?
t = 2πr/v
I = e/t = ev/2πr = (1.6*10? ¹? * 2.2*10? )/ (2 * 22/7 * 0.5*10? ¹? )
I ≈ 1.12*10? ³ A = 1.12 mA = 112 * 10? ² mA
New answer posted
10 months agoContributor-Level 10
M = 9.85*10? ² A/m²
I = 5*10? kg-m²
T = 5s/10osc = 0.5 sec
B =?
T = 2π√ (I/MB)
B = 4π²I/ (MT²) = (4*9.85*5*10? )/ (9.85*10? ² * 0.5²)
B = (20*10? )/ (10? ² * 0.25) = 800*10? = 0.8*10? ³ T = 8mT
New answer posted
10 months agoContributor-Level 10
Amplitude of sidebands = µAc/2
Here µ = Am/Ac = 5/15 = 1/3
Amplitude = (1/3) (15)/2 = 2.5 V
a/10 = 2.5 => a = 25
b/10 = 2.5 => b = 25
a/b = 1
New answer posted
10 months agoContributor-Level 10
For photon, λ? = h/p = 6.6*10? ³? /10? ²? = 6.6*10? m
For a particle, λ? = h/mv = 6.6*10? ³? / (9.1*10? ³¹ * 10? ) ≈ 7.25*10? ¹? m
λ? /λ? = 6.6*10? / 7.25*10? ¹? ≈ 910
New answer posted
10 months agoContributor-Level 10
When T? & T? are connected, at steady state current, I becomes
I = 6V/6Ω = 1A
Now when T? & T? are connected, the current through the inductor, just after connecting, remains same. So
V? Ω = 1A * 3Ω = 3volt.
New answer posted
10 months agoContributor-Level 10
Light rays travel undeviated if the refractive index of the medium does not change for any value of angle of incidence.
i.e. n? = n?
1.2 + 10.8*10? ¹? /λ² = 1.45 + 1.8*10? ¹? /λ²
9.0*10? ¹? /λ² = 0.25
λ² = 36*10? ¹?
λ = 6*10? m = 600 nm
New answer posted
10 months agoContributor-Level 9
ε = |dΦ/dt| = A|dB/dt|
Given B (t), dB/dt = (4/π) * 10? ³ * (-1/100)
ε = (π * 1²) * | (4/π) * 10? ³ * (-1/100)|
= 4 * 10? V
To find when B=0:
B = 0 ⇒ 1 - t/100 = 0
⇒ t = 100 second
Energy Dissipated, E = P * t = (ε²/R) * t
E = (4*10? )² / (2*10? ) * 100 = 80mJ
New answer posted
10 months agoContributor-Level 10
As we know, β = Ic/Ib = 24 (Given)
R = 1000Ω, ΔV = 0.6V, Ic = ΔV/R = 0.6/1000 = 6*10? A
So, Ib = Ic/β = (6*10? )/24 = 25*10? A
or Ib = 25µA
New answer posted
10 months agoContributor-Level 9
We know, μ? = 1 + χ?
B? ∝ μ?
B ∝ μ
(ΔB/B? ) = (B-B? )/B? = (μ-μ? )/μ? = μ/μ? - 1 = μ? - 1 = χ?
% (ΔB/B) = χ? * 100 = 2.2 * 10? * 100 = 22/10?
(Note: The value for χ? in the source image appears to have a typo as 2.2 * 10? , it has been corrected to 2.2 * 10? to match the final answer.)
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 703k Reviews
- 1850k Answers


