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New answer posted

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 = 1/λ = 30*10? ³ sec.
C = 200µF, R
Q/A = constant [Given]
A = A? e? & Q = Q? e? /?
Q/A = (Q? /A? ) e^ (-t/RC + λt) = constant
For this to be constant, the exponent must be zero.
-t/RC + λt = 0
1/RC = λ
R = 1/ (λC) = /C = 30*10? ³/200*10? = 150 Ω

New answer posted

10 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

r = 0.5Å = 0.5*10? ¹? m
v = 2.2*10? m/s
I =?
t = 2πr/v
I = e/t = ev/2πr = (1.6*10? ¹? * 2.2*10? )/ (2 * 22/7 * 0.5*10? ¹? )
I ≈ 1.12*10? ³ A = 1.12 mA = 112 * 10? ² mA

New answer posted

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

M = 9.85*10? ² A/m²

I = 5*10? kg-m²

T = 5s/10osc = 0.5 sec

B =?

T = 2π√ (I/MB)

B = 4π²I/ (MT²) = (4*9.85*5*10? )/ (9.85*10? ² * 0.5²)

B = (20*10? )/ (10? ² * 0.25) = 800*10? = 0.8*10? ³ T = 8mT

New answer posted

10 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Amplitude of sidebands = µAc/2
Here µ = Am/Ac = 5/15 = 1/3
Amplitude = (1/3) (15)/2 = 2.5 V
a/10 = 2.5 => a = 25
b/10 = 2.5 => b = 25
a/b = 1

New answer posted

10 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

For photon, λ? = h/p = 6.6*10? ³? /10? ²? = 6.6*10? m
For a particle, λ? = h/mv = 6.6*10? ³? / (9.1*10? ³¹ * 10? ) ≈ 7.25*10? ¹? m
λ? /λ? = 6.6*10? / 7.25*10? ¹? ≈ 910

New answer posted

10 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

When T? & T? are connected, at steady state current, I becomes
I = 6V/6Ω = 1A
Now when T? & T? are connected, the current through the inductor, just after connecting, remains same. So
V? Ω = 1A * 3Ω = 3volt.

New answer posted

10 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Light rays travel undeviated if the refractive index of the medium does not change for any value of angle of incidence.
i.e. n? = n?
1.2 + 10.8*10? ¹? /λ² = 1.45 + 1.8*10? ¹? /λ²
9.0*10? ¹? /λ² = 0.25
λ² = 36*10? ¹?
λ = 6*10? m = 600 nm

New answer posted

10 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

ε = |dΦ/dt| = A|dB/dt|
Given B (t), dB/dt = (4/π) * 10? ³ * (-1/100)
ε = (π * 1²) * | (4/π) * 10? ³ * (-1/100)|
= 4 * 10? V
To find when B=0:
B = 0 ⇒ 1 - t/100 = 0
⇒ t = 100 second
Energy Dissipated, E = P * t = (ε²/R) * t
E = (4*10? )² / (2*10? ) * 100 = 80mJ

 

New answer posted

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

As we know, β = Ic/Ib = 24 (Given)
R = 1000Ω, ΔV = 0.6V, Ic = ΔV/R = 0.6/1000 = 6*10? A
So, Ib = Ic/β = (6*10? )/24 = 25*10? A
or Ib = 25µA

New answer posted

10 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

We know, μ? = 1 + χ?
B? ∝ μ?
B ∝ μ
(ΔB/B? ) = (B-B? )/B? = (μ-μ? )/μ? = μ/μ? - 1 = μ? - 1 = χ?
% (ΔB/B) = χ? * 100 = 2.2 * 10? * 100 = 22/10?
(Note: The value for χ? in the source image appears to have a typo as 2.2 * 10? , it has been corrected to 2.2 * 10? to match the final answer.)

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