Class 12th
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New answer posted
10 months agoContributor-Level 10
P1 + P2 + P3 = 59
P1 and P2 → minimize
Then P3 → minimum i.e. 47
P1 | P2 | P3 |
5 | 7 | 47 |
5 | 11 | 43 |
3 | 13 | 43 |
5 | 13 | 41 |
5 | 17 | 37 |
3 | 19 | 37 |
5 | 23 | 31 |
7 | 23 | 29 |
So, only possible value of P3 can take → 29, 31, 37, 41, 43, and 47
Total 6 values
New answer posted
10 months agoContributor-Level 10
______equation 1
i.e. y = 90+y,
1≤ y1 ≤9
y1 is odd
Equation 1 becomes
y1 can take 1,3,5,9
y=91, 93, 95, 99
New answer posted
10 months agoContributor-Level 10
Sol1 | 20percent (0.6) | 3L |
Sol2 | 40percent (0.4) | 1L |
Sol3 | 1L | 4L |
Sol4 | XL | 3L |
Sol5 | 3.5L | 7L |
1 + x = 3.5
x= 2.5
Required percent y =
New answer posted
10 months agoContributor-Level 10
x, a, b, y are in GP
a = xr
b = xr2
y = xr3
r =
rewrite,
a = x2/3.y1/3
b = x1/3.y2/3
a * b = x * y
a3 + b3 = x2y + y2 x
= xy (x+y)
= xy (2A) ……………
Hence, n = 2
New answer posted
10 months agoContributor-Level 10

Let the side of = a
CD = a/2
Let EC = x
In GEC
GE/EC = tan60 =
GE = x
DE = a/2 – x = FG = HF
GE = HG
x = a – 2x
x =
GE = x =

r = side of square ÷ 2
r=
ratio = a/r
=
=
New answer posted
10 months agoContributor-Level 10
The potential
at any point, at distance
from centre of dipole
At axial point where
At axial point where
New answer posted
10 months agoContributor-Level 10
(d):3515.2 – 3380 = 135.2 = SI on Rs. 3380 for one year.
By SI formula, 135.2 = or R = 4 %
Now we have 3380 = P (1.04)2 or P = Rs. 3125
New answer posted
10 months agoContributor-Level 10
(c):Let speed of passenger train be x m/s.
x = 6.94 m/sec = 25 kmph.
New answer posted
10 months agoContributor-Level 10
(c):We have 4 men = 5 women 1 man = women, 2 women = 4 boys, 1 women = 2 boys women = 2 * boys = or 1 man = women = boys
Now 2M + 3W+ 4B = 2 * B + 3 * 2B + 4B = 15 B Boys
Or 15 Boys do the work in 10 days (10 hectares) 6M + 4W + 7B = (6 * + 4 * 2 + 7) B = 30
Boys 30 boys will do 16 hectares of work in 8 days.
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