Class 12th

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

(d):The three different Maths books can be arranged in 3! ways. Now there are four places created for the Chemistry books such that they are not together.

The four Chemistry books can be arranged in the available four places in 4! ways.

New answer posted

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

In the first group, one question can be selected or can be rejected; so three questions can be dealt with in 2 * 2 * 2 ways, but this includes the case when all three questions have been left; so they can be selected in 23 – 1 = 7 ways. Similarly four questions of the second group can be selected in 24 – 1 = 15 ways. Thus all seven questions can be selected in 15 * 7 = 105 ways; but this includes the case when all questions have been solved; hence leaving that case, total number of ways required is 105 – 1 = 104

New answer posted

5 months ago

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R
Raj Pandey

Contributor-Level 9

Every number between 1000 and 2000, which is divisible by five and which can be formed by the given digits, must contains 5 in unit's place and 1 in thousand's place. Thus we are left with four digits out of which we are to place two between 1 and 5, which can be done in 4P2 = 12 ways. Hence, 12 numbers can be formed.

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

(c):Discount = 3%

Price = 650.

S.P = .97 * 650 = 630.5

New answer posted

5 months ago

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R
Raj Pandey

Contributor-Level 9

Let L be the vertical distance between the centers of two adjacent balls.

L = [ ( 2 r ) 2 r 2 ] = r 3

Also, if the box can hold n sphere then (n – 1) L + 2r

≤ 9r [ the last ball height = 2r]

( n 1 ) 3 r 7 r

n 7 3 + 1

n ≤ 5.04

Since, n is a natural number.

n = 5

So, the box can hold maximum of 5 spheres.

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

(b):Total time required to empty it =

1 (1313.5)=21hours.

New answer posted

5 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

9B + 3 + 5G + 4 = 200  9B + 5G = 193

The positive integer solutions are (B, G) = (2, 35) (7, 25) (12, 17) (17, 8)

Only one of the (B, G) gives G > B and 9B + 3 > 100, i.e. (B, G) = (12, 17)

 

17 * 5 = 85

New answer posted

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

(a):Let, s be the speed of stream.

So, 8 + s = 2 (8 – s)

s = 8/3 mph

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