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Class 12th English

Percentage Sales of Different brands of Rice in Delhi in Two Different Years

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Payal Gupta

Contributor-Level 10

Required Ratio

= Increase in R4/ Increase in R3

$= \frac{2046}{2028} = 1$

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Class 12th English

Percentage Sales of Different brands of Rice in Delhi in Two Different Years

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Payal Gupta

Contributor-Level 10

$Ratio = \frac{\frac{2.1}{100} * 2400}{\frac{17}{100} * 10200} = 0.29$

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Class 12th English

Percentage Sales of Different brands of Rice in Delhi in Two Different Years

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Payal Gupta

Contributor-Level 10

R3 $= \frac{26}{100} * 10200 - \frac{26}{100} * 2400 = 2028$

R4 $= \frac{25}{100} * 10200 - \frac{26}{100} * 2400 = 2046$

R5 $= \frac{24 * 10200}{100} - \frac{26 * 2400}{100} = 1812$

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Class 12th English

Directions for questions: Answer the questions on the basis of the information given below.

Percentage Sales of Different brands of Rice in Delhi in Two Different Years

The percentage change in the sales of R2 Rice in 2010 is approximately

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Payal Gupta

Contributor-Level 10

Percentage change in R2 Sales

$= (\frac{(\frac{8 * 10200}{100}) - (\frac{12 * 2400}{100})}{(\frac{12 * 2400}{100})}) * 100 = 183 %$

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11 months ago

Class 12th English

The given graphs which show the Seats won and the percentage of valid votes polled for different political parties in a state for different election years

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Payal Gupta

Contributor-Level 10

Total votes in 2009 = (2.24/44.8)*100=5 crore

Total Votes in 1999 = (1.228/30.7)*100= 4 crore

4 cr. is 20% less than 5 cr.

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Class 12th English

The following table gives year wise and course wise admission to a college.

Sports	2016	2017	2018	2019	2021	2022
Course 1	160	200	250	150	140	160
Course 2	40	80	95	100	110	130
Course 3	80	120	120	110	150	130
Course 4	70	90	50	30	60	80
Course 5	100	140	180	200	250	300
Course 6	10	10	20	10	10	10
Total	460	640	715	600	720	810

For which course the total admission for all the 6 years is closest to the total admission for any one of the years?

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Payal Gupta

Contributor-Level 10

Total admission for each course:

Course 2 = 40 + 80 + 95 + 100 + 110 + 130 = 555,

Course 5 = 100 + 140 + 180 + 200 + 250 + 300 = 234,

Course 4 = 14 + 18 + 10 + 6 + 12 + 16 = 1170,

Course 3 = 80 + 120 + 120 + 110 + 150 + 130 = 710.

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11 months ago

Class 12th English

The following table gives year wise and course wise admission to a college.

Sports	2016	2017	2018	2019	2021	2022
Course 1	160	200	250	150	140	160
Course 2	40	80	95	100	110	130
Course 3	80	120	120	110	150	130
Course 4	70	90	50	30	60	80
Course 5	100	140	180	200	250	300
Course 6	10	10	20	10	10	10
Total	460	640	715	600	720	810

In which year the admission to course 1 as percentage of total admission?

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Payal Gupta

Contributor-Level 10

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New answer posted

11 months ago

Class 12th NCERT Solutions

What chapters and units are covered in the Class 12 Physics NCERT revision notes?

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Esha Garg

Beginner-Level 5

Subject experts at Shiksha has designed these Class 12 CBSE Notes in concise and lucid language. We offer complete coverage of topics and subtopics of all chapters of class 12 physics. We have covered following Class 12 Physics Chapters and their subtopics.

Class 12 Physics Chapter 1 Electric Charges and Fields
Class 12 Physics Chapter 2 Electrostatic Potential and Capacitance
Class 12 Physics Chapter 3 Current Electricity
Class 12 Physics Chapter 4 Moving Charges and Magnetism
Class 12 Physics Chapter 5 Magnetism and Matter
Class 12 Physics Chapter 6 Electromagnetic Induction
Class 12 Physics Chapter 7 Alternating Current
Class 12 Physics Cha

...more

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Class 12th Chemistry

The sol given below with negatively charged colloidal particles is:

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alok kumar singh

Contributor-Level 10

When AgNO₃ added to Kl solution, it form precipitate of Agl (s) which absorb I^- ions from Kl and colloidal particles become negatively charged.

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Class 12th Chemistry

The number of non-ionisable hydrogen atoms present in the final product obtained from the hydrolysis of PCl₅ is:

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alok kumar singh

Contributor-Level 10

All hydrogens are attached to oxygen are ionisable.

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