Class 12th

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New answer posted

11 months ago

0 Follower 33 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

11 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Current through zener diode,

l z = 2 4 1 0 1 1 0 5 m A = 1 2 m A              

Power across zener diode,

P z = V z . l z = 1 0 * 1 2 = 1 2 0 m W          

New answer posted

11 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

τ = M B s i n θ

= 0 . 2 * 3 4 * ( 0 . 1 ) 2 * 2 0 * 1 0 3 * s i n 9 0 °

= 3 * 1 0 5 N m              

 

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

ε m a x = n B A ω

= 20 * 3.0 * 10-2 * 3.14 * (0.08)2 * 50

= 60.3 * 10-2 V

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

ω m o d u l a t i o n = 2 π f m o d u l a t i o n        

f m o d u l a t i o n = ω m o d u l a t i o n 2 π

= 1 2 5 6 0 2 π         

= 2000 Hz

= 2kHz

New answer posted

11 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

P = 2 l C P radiation pressure

= 2 C ( 1 2 ε 0 E 0 2 C )

= ε 0 E 0 2 = ( 8 . 8 5 * 1 0 1 2 ) * ( 2 0 0 ) 2 = 3 5 4 * 1 0 9 N / m 2

New answer posted

11 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

As image coincides with the object, image formed by convex lens should be at the centre of curvature of the convex mirror. If the convex mirror is removed, then, also, image formed the convex lens is at the same location.

Distance of image from object = 12 + 8 + 2 * 15 = 50 cm

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

For first fringe

d y 1 D = 1 * λ 1 [ n = 1 ] λ 1 Red wavelength

d y 2 D = 1 * λ 2 [ n = 1 ] λ 2 violet wavelength

d D ( y 1 y 2 ) = λ 1 λ 2           

y 1 y 2 = D d ( λ 1 λ 2 )        

= 0 . 3 * 1 0 3 1 . 5 ( 3 . 5 2 ) * 1 0 3

= 300 * 10-9

= 300 nm

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

2nqV = 1 2 m v 2

n = m v 2 4 q V

= 1 . 6 7 * 1 0 2 7 * ( 0 . 5 * 1 0 8 ) 2 4 * 1 . 6 * 1 0 1 9 * 1 2 * 1 0 3 = 5 4 3  

             

New answer posted

11 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

  τ 2 = B 1 M 2 S m 9 0 °

= B1 M2

= ( μ 0 4 π * m 1 r 3 ) * m 2        

= 1 0 7 1 1 3 * 1

= 10-7 N – m

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