Class 12th

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New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

[ P t C l 4 ] 2 + H 2 O ? [ P t ( H 2 O ) C l 3 ] + C l  

At equilibrium  d x d t = 0 , hence

0 = d [ [ P t C l 4 ] 2 ] d t = 4 . 8 * 1 0 5 [ [ P t C l 4 ] 2 ] 2 . 4 * 1 0 3 [ [ P t ( H 2 O ) C l 3 ] ] [ C l ]           

K c = K f K b = 4 . 8 * 1 0 5 2 . 4 * 1 0 3              

= 2 * 10-2

= 0.02

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Cu2Cl2 + Water -> Insoluble

AgCl + Water -> Insoluble

ZnCl2 + Water -> Colouless solution

CuCl2 + Water -> Coloured solution due to 3d9 electronic configuration.

New answer posted

11 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Molar conductivity measured at infinite dilution is called limiting molar conductivity. Hence at infinite dilution stage, both strong electrolyte (KCl) and weak electrolyte (CH3COOH) have identical value of conductivity. Therefore statement – I is false.

Statement – II is also false because molar conductivity increases by the decreasing the concentration of electrolyte.

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Molar weight of BaSO4 = 233 gram

233 gm of BaSO4 has 32 gm of S content

Hence 1.44 gm of BaSO4 has ( 3 2 * 1 . 4 4 2 3 3 ) g of S content = 0.1977 gm of 'S'

Weight of sulphur = 0.2 gram (the nearest)

Weight of organic sample = 0.471 gram

% of Sulphur = 0 . 2 * 1 0 0 0 . 4 7 1 = 4 2 . 4 6 %  

the nearest = 42%

New answer posted

11 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

11 months ago

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P
Payal Gupta

Contributor-Level 10

R4 → D5 → DR2

The least cost to reach to AAB is for AE. And that is BD to AE is zero.

New answer posted

11 months ago

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P
Payal Gupta

Contributor-Level 10

If you look for large figures you would find them in both tables in D5.

 the largest cost = 1157.7 + 1035.3

= 2193.00

New answer posted

11 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Yellow precipitate is Agl (s) which only produce by structure IV

New answer posted

11 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

Number of refineries = 6

Number of depots = 7

Number of districts = 9

Therefore, number of possible ways to send petrol from any refinery to any district is 6 * 7 * 9 = 378.

New answer posted

11 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

? 0 = h υ 0

= 6 . 6 * 1 0 3 4 * 1 . 3 * 1 0 1 5 J

= 8 . 5 8 * 1 0 1 9 J

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