Class 12th
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New answer posted
10 months agoContributor-Level 10
This is a matching answer type question as classified in NCERT Exemplar
Correct option is (i)
In XeF6, the central Xe atom undergoes sp3d3 hybridisation and the molecular geometry is distorted octahedral with 1 lone pair and 6 bond pairs of electrons.
In XeO3, the central Xe atom undergoes sp3 hybridisation and the molecular geometry is pyramidal with 1 lone pair and 3 bonding domains of electrons.
In XeOF4, the central Xe atom undergoes sp3d2 hybridization and the molecular geometry is square pyramidal with 1 lone pair and 5 bond pairs of electrons.
In XeF4, the central Xe atom undergoes&nb
New answer posted
10 months agoContributor-Level 10
This is a Objective Type Question as classified in NCERT Exemplar
Sol:
New answer posted
10 months agoContributor-Level 10
This is a Objective Type Question as classified in NCERT Exemplar
Sol:
New answer posted
10 months agoContributor-Level 10
This is a assertion and reason answer type question as classified in NCERT Exemplar
Correct option is (i)Here, the S atom is surrounded by 6F atoms, so it's complected for H2O to attack SF6, but in case of SF4, it's surrounded by 4F atoms, so it's to attack H2O.
New question posted
10 months agoNew answer posted
10 months agoContributor-Level 10
This is a assertion and reason answer type question as classified in NCERT Exemplar
Correct option is (i)
When NaCl reacts with concentrated H2SO4, it produces colourless fumes with a pungent smell, but when MnO2 is added, the fumes turn greenish yellow. MnO2 oxidizes HCl to chlorine gas, which then turns greenish yellow.
New answer posted
10 months agoContributor-Level 10
This is a Objective Type Question as classified in NCERT Exemplar
Sol:
New answer posted
10 months agoContributor-Level 10
This is a assertion and reason answer type question as classified in NCERT Exemplar
Correct option is (i)
The rhombic and the monoclinic forms of sulphur exist as S8 . Oxygen forms a p\pi - p\pi multiple bond due to its small size and short bond length, but Pπ- Pπ bonding is not possible because of sulphur's larger atomic size.
New answer posted
10 months agoContributor-Level 10
This is a Objective Type Question as classified in NCERT Exemplar
Sol:
New answer posted
10 months agoContributor-Level 10
This is a assertion and reason answer type question as classified in NCERT Exemplar
Correct option is (ii)
Because H2SO4 is a stronger oxidising agent and HI is a stronger reducing agent, H2SO4 oxidizes and is reduced to SO2.
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