CSIR NET
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New answer posted
11 months agoContributor-Level 7
Candidates can check the CSIR NET 2026 Mathematical Science Analysis for June session in the table below based on the students' review.
Part Name | Total MCQs | Total MCQs to be Attempted | Good Attempts | Difficulty Level |
|---|---|---|---|---|
Part A | 20 | 15 | To be updated here | To be updated here |
Part B | 40 | 25 | To be updated here | To be updated here |
Part C | 60 | 20 | To be updated here | To be updated here |
Total | 120 | 60 | To be updated here | To be updated here |
New answer posted
11 months agoContributor-Level 7
The CSIR NET stands for the Council of Scientific and Industrial Research National Eligibility Test. It determines the eligibility of Indian nationals for the 'award of Junior Research Fellowship and appointment as Assistant Professor.' Also, appointment as 'Assistant Professor and admission to Ph.D.' and 'admission to Ph.D. only' in several Indian universities and colleges.
New answer posted
11 months agoContributor-Level 7
The CSIR NET application form was released at csirnet.nta.nic.in. Candidates were advised to read the instructions for payment carefully before paying the application fee and also read the eligibility criteria before applying for the exam.
New answer posted
11 months agoContributor-Level 10
The NTA CSIR NET application correction dates for the June session were June 22 to 23, 2026. It is advised to the candidates that they should fill all the details properly in the registration form. Because after the last date, candidates will not be allowed to make corrections.
New answer posted
11 months agoContributor-Level 7
The last date to apply for the CSIR UGC NET June session was June 19. Candidates could pay the application fee until June 20.
New answer posted
a year agoContributor-Level 7
Candidates should follow a balanced approach. No doubt books help in conceptual clarity, and a candidate can study in detail. On the other hand, online platforms provide lectures through video, have updated notes, cover current affairs as well, etc.
New answer posted
a year agoContributor-Level 7
As per the official website, stipend of a JRF selected through CSIR-UGC National Eligibility Test (NET) will be Rs 37,000/ p.m for the first two years. In addition, annual contingent grant of Rs. 20,000/- per fellow will also be provided to the fellow.
New answer posted
a year agoContributor-Level 7
Yes. Candidates clear the CSIR UGC NET exam in three months. But to pass the exam proper strategy is required. They make study plans, do revisions, solve question papers, practice tests, etc. If a candidate study properly then nothing is impossible to crack.
New answer posted
a year agoContributor-Level 7
The CSIR NET exam consists of five subjects some of them are Maths, Physical Science, Chemical Science, etc. Part A in the exam is common for all candidates and Part B and C is subject-specific. Candidates need to select one subject and prepare well to clear the examination.
New answer posted
a year agoContributor-Level 7
The CSIR NET 2025 June session city slip released on the official website at csirnet.nta.ac.in. The CSIR NET 2025 exam is conducted on July 28, 2025.
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