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4 months ago

Determinants Class 12th

65. $[\begin{array}{l} 2 - 3 5 \\ 3 2 - 5 \\ 1 1 - 5 \end{array}],find A^{- 1} .Using A^{- 1}$ solve the system of equations.

$\begin{array}{l} 2 x - 3 y + 5 z = 11 \\ 3 x + 2 y - 4 z = - 5 \\ x + y - 2 z = - 3 \end{array}$

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Vishal Baghel

Contributor-Level 10

Kindly go through the solution

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New answer posted

4 months ago

Determinants Class 12th

64. $\begin{array}{l} x - y + 2 z = 7 \\ 3 x + 4 y - 5 z = - 5 \\ 2 x - y + 3 z = 12 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of eqⁿ can be written in matrix form as

AK = B

∴ x= 2, y = 1 and z = 3 .

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New answer posted

4 months ago

Determinants Class 12th

63. $\begin{array}{l} 2 x + 3 y + 3 z = 5 \\ x - 2 y + z = - 4 \\ 3 x - y - 2 z = 3 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of equation can be represented in matrix form as AK = B

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New answer posted

4 months ago

Determinants Class 12th

62. $\begin{array}{l} x - y + z = 4 \\ 2 x + y - 3 z = 0 \\ x + y + z = 2 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of eqⁿ can be written in matrix form as AK = B.

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New answer posted

4 months ago

Determinants Class 12th

61. $\begin{array}{l} 2 x + y + z = 1 \\ x - 2 y - z = \frac{3}{2} \\ 3 y - 5 z = 9 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of solution in matrix form is AK = B.

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New answer posted

4 months ago

Determinants Class 12th

Kindly Consider the following

60. $\begin{array}{l} 5 x + 2 y = 3 \\ 3 x + 2 y = 5 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of equation in matrix form is

AK = B

0 0

New answer posted

4 months ago

Determinants Class 12th

Kindly Consider the following

59. $\begin{array}{l} 4 x - 3 y = 3 \\ 3 x - 5 y = 7 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of eqⁿ can be written in matrix form as

AK = B

0 0

New answer posted

4 months ago

Determinants Class 12th

Kindly Consider the following

58. $\begin{array}{l} 2 x - y = - 2 \\ 3 x + 4 y = 3 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of eqⁿ in matrix form is AK = B

0 0

New answer posted

4 months ago

Determinants Class 12th

Kindly Consider the following

57. $\begin{array}{l} 5 x + 2 y = 4 \\ 7 x + 3 y = 5 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of eqⁿ in matrix form is AK = B.

Then, |A| = 5 x 3 - 7 x 2 = 15 - 14 = 1 ≠ 0

∴ The system has a unique solution.

∴ k = 2 and y = -3

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New answer posted

4 months ago

Determinants Class 12th

56. $\begin{array}{l} 5 x - y + 4 z = 5 \\ 2 x + 3 y + 5 z = 2 \\ 5 x - 2 y + 6 z = - 1 \end{array}$

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Vishal Baghel

Contributor-Level 10

The given system of eqⁿ in matrix form is AK = B

= 5 x 28 -13 + 4 x (-9)

= 140 - 13 - 76

= 51 ≠ 0 .

The given system of eqⁿ are consistent

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