Dual Nature of Radiation and Matter

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a month ago

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R
Raj Pandey

Contributor-Level 9

Based on theory

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a month ago

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V
Vishal Baghel

Contributor-Level 10

z² * (13.6) (1 - ¼) = 3 * (13.6)
z = 2 . (i)
h/√2mk? = (1/2.3) * h/√2mk?
=> k? = (2.3)²k? = 5.25k? (ii)
Now, k? = E? - Φ
k? = E? - Φ = z²E? - Φ
∴ k? /k? = (10.2 - Φ)/ (4 * 10.2 - Φ) = 1/5.25
=> Φ = 3eV

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

  K . E 1 = 1 2 3 0 8 0 0 ? - (i)

  K . E 2 = 2 K . E 1 = 1 2 3 0 5 0 0 ? - (ii)

from (i) & (ii)

? = 0 . 6 1 5  ev

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

hu = hu0 + K.E

Cases u = 2u0

h2u0 = hu0 + K.E1

K.E1 = hu0

1 2 m v 1 2 = h υ 0

v 1 2 = 2 h υ 0 m  

v 1 = 2 h υ 0 m - (1)      

Now, cases 2

h 5u0 = hu0 + k.E2

k.E2 = 4hu0

1 2 m v 2 2 = 4 h υ 0

v2 =     8 h υ 0 m   - (2)

v 2 v 1 = 8 2 = 2          

v2 = 2v1

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4 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

f(x)=2x23x2x2=2x24x+x2x2=2x(x2)+1(x2)x2=(2x+1)(x2)x2=2x+1limx2f(x)=2x+1=limh02(2h)+1=4+1=5limx2+f(x)=2x+1=limh02(2+h)+1=4+1=5limx2f(x)=5Aslimx2f(x)=limx2+f(x)=limx2f(x)=5Hence,f(x)iscontinuousatx=2.

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4 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- p=100W

λ 1= 1nm

λ 2= 500nm

Also n1and n2 represent number of photon of x-rays and visible light emitted from the two sources per sec

E/t=P=n1hc/ λ 1=n2hc/ λ 2

So n1/ λ 1 = n2/ λ 2

So n1/n2= 1/500

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4 months ago

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- In photoelectric effect, we can observe that most electrons get scattered into the metal by absorbing a photon.Thus, all the electrons that absorb a photon doesn't come out as photoelectron. Only a few come out of metal whose energy becomes greater than the work function of metal.

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- According to first statement, when the materials which absorb photons of shorter wavelength has the energy of the incident photon on the material is high and the energy ofemitted photon is low when it has a longer wavelength.

But in second statement, the energy of the incident photon is low for the substances which has to absorb photons of larger wavelength and energy of emitted photon is high to emit light of shorter wavelength. This means in this statement material has to supply the energy for the emission of photons.But this is not possible for a s

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4 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- (i) Here it is given that, an electron absorbs 2 photons each of frequency ν then ν where, v′ is the frequency of emitted electron.

Given, Emax= hv- ? 0

Now, maximum energy for emitted electrons is Emax= h2v- ? 0 = 2 h v - ? 0

(ii) The probability of absorbing 2 photons by the same electron is very low. Hence, such emission will be negligible

 

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