Electric Charges and Fields

1.4 

(a) Electric charge of a body is quantized, this means that only integers (1,2,3, ….n) number of electrons can be transferred from one body to the other. Charges are not transferred in fraction. Hence, a body possesses total charge only in integers.

(b) In macroscopic i.e. large scale char

1.3 The units of the given equation 

$\frac{{ke}^2}{G{m}_e{m}_p}$ is

e = Electric charge in C

k = $\frac{1}{4\pi {?}_0}$ in N $m^2{C}^{-2},$ where ${?}_0$ = Permittivity of free space = 8.854 $\times {10}^{-12}$ $C^2{N}^{-1}$ $m^{-2}$

G = Gravitational constant = N $$

$m^2{kg}^{-2}$

${\mathrm{m}}_{\mathrm{e}}=\mathrm{m}\mathrm{a}\mathrm{s}\mathrm{s}\mathrm{}\mathrm{o}\mathrm{f}\mathrm{}\mathrm{e}\mathrm{l}\mathrm{e}\mathrm{c}\mathrm{t}\mathrm{r}\mathrm{o}\mathrm{n}\mathrm{}\mathrm{i}\mathrm{n}\mathrm{}\mathrm{k}\mathrm{g},\mathrm{}\mathrm{}{\mathrm{m}}_{\mathrm{p}}=\mathrm{m}\mathrm{a}\mathrm{s}\mathrm{s}\mathrm{}\mathrm{o}\mathrm{f}\mathrm{}\mathrm{p}\mathrm{r}\mathrm{o}\mathrm{t}\mathrm{o}\mathrm{n}\mathrm{}\mathrm{i}\mathrm{n}\mathrm{}\mathrm{k}\mathrm{g}$

Therefore

$\frac{{ke}^2}{G{m}_e{m}_p}$ = $\frac{\left[\mathrm{N}{m}^2{C}^{-2}\right]\times \left[C^2\right]}{\left[\mathrm{N}{m}^2{kg}^{-2}\right]\left[kg\right]\left[kg\right]}$= $M^0{L}^0{T}^0$

So the given equation is dimensionless

We have the following

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Ma

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