Electromagnetic Waves

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New answer posted•a year ago

Electromagnetic Waves Class 12th

The quantities x = 1/√(µ₀ε₀), y = E/B and z = 1/CR are defined where C-capacitance, R Resistance, l-length, E-Electric field, B-magnetic field and ε₀, µ₀, - free space permittivity and permeability respectively. Then:

10 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

x = 1/√ (µ? ε? ) = speed ⇒ [x] = [L¹T? ¹]
y = E/B = speed ⇒ [y] = [L¹T? ¹]
z = l/ (RC) = l/τ ⇒ [z] = [L¹T? ¹]
So, x, y, z all have the same dimensions.

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New answer posted•a year ago

Electromagnetic Waves Class 12th

The correct match between the entries in column I and column II are:

8 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Energies of given Radiation can have
The following relation
Eγ-Rays > EX-Rays > Emicrowave > EAM Radiowaves
∴ λγ-Rays < λX-Rays < λmicrowave < λAM Radiowaves
According to tres.
(a) Microwave → 10? ³ m
(b) Gamma Rays → 10? ¹? m (ii)
(c) AM Radio wve → 100 m (i)
(d) X-Rays → 10? ¹? m

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New answer posted•a year ago

Electromagnetic Waves Class 12th

If the magnetic field in a plane electromagnetic wav is given by $\overset{?}{B} = 3 \times 10^{- 8}$ $s i n ? (1.6 \times 10^{3} x + 48 \times 10^{10} t) j T$ $^{}$ $(^{}^{})$ , then what will be expression for electric field?

4 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

$m = L, b = R, k = \frac{1}{c}$ (speed of light in vacuum)

$\frac{E_{0}}{B_{0}} = C$

So, $E_{0} = B_{0} C = 3 \times 10^{- 8} \times 3 \times 10^{8} = 9 N / C$

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New answer posted•a year ago

Electromagnetic Waves Class 12th

An electromagnetic wave of frequency 3GHz enters a dielectric medium of relative electric permittivity 2.25 from vacuum. The wavelength of this wave in that medium will be………………….× 10^-² cm.

2 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

f = 3GHz = 3 × 10⁹ Hz

$λ_{v a c u u m} = \frac{v}{f} = \frac{3 \times 1 0^{8} m / s}{3 \times 1 0^{9} / s} = 1 0^{- 1} m = 0.1 m$

$λ_{v a c u u m} = \frac{λ_{v a c u u m}}{μ_{m e d i u m}} = \frac{0.1}{μ_{m e d i u m}}$

$μ_{m e d i u m} = \sqrt[]{μ_{r} \in_{r}} = \sqrt[]{1 \times 2.25} = 1.5$

$∴ μ_{m e d i u m} = \frac{0.1 m}{1.5} = 0.0667 m = 6.67 c m = 667 \times 1 0^{- 2} c m$

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New answer posted•a year ago

Electromagnetic Waves Class 12th

Match List – I with List – II

List – I                                                                               List – II

(a) Source of microwave frequency                           (i) Radioactive decay of nucleus

(b) Source of infrared frequency                                (ii) Magnetron

(c) Source of Gamma Rays                                           (iii) Inner shell electrons

(d) Source of X-rays                                                       (iv) Vibration of atoms and molecules

(v) LASER

(vi) RC circuit

Choose the correct answer from the option given below:

3 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

(A) Source of microwave frequency => Magnetron

(B) Source of infrared frequency =>Vibration of atoms and molecules

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New answer posted•a year ago

Electromagnetic Waves Class 12th

Intensity of sunlight is observed as 0.092 Wm^-² at a point in free space. What will be the peak value of magnetic field at that point?

 $(ε_{0} = 8.85 \times 1 0^{- 12} C^{2} N^{- 1} m^{- 2})$

10 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

$l = \frac{1}{2} C ε_{0} E_{0}^{2} = \frac{1}{2} C ε_{0} {(C B_{0})}^{2} = \frac{1}{2} C^{3} ε_{0} B_{0}^{2}$

$B_{0} = \sqrt[]{\frac{2 l}{ε_{0} C^{3}}}$

$= \sqrt[]{\frac{2 \times 0.092}{8.85 \times 1 0^{- 12} \times 27 \times 1 0^{24}}}$

$= 2.27 \times 1 0^{- 8} T$

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New answer posted•a year ago

Electromagnetic Waves Class 12th

In an electromagnetic wave the electric field vector magnetic field vector are given as $\vec{E} = E_{0} \hat{i} a n d \vec{B} = B_{0} \hat{k}$  respectively. The direction of propagation of electromagnetic wave is along.

3 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

As we know that direction of propagation $(\hat{p})$ of wave is given as

$\hat{p} = \hat{E} \times \hat{B} = \hat{i} \times \hat{k} = (- \hat{j})$

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New answer posted•a year ago

Electromagnetic Waves Class 12th

The magnetic field vector of an electromagnetic wave is given by B = B₀ = $\frac{\hat{i} + \hat{j}}{\sqrt[]{2}} c o s (k z - ω t);$  where $\hat{i}, \hat{j}$  represents unit vector along x and y-axis respectively. At t = 0 s, two electric charges q1 of 4π coulomb and q2 and 2p coulomb located at $(0, 0, \frac{π}{k}) a n d (0, 0, \frac{3 π}{k}),$  respectively, have the same velocity of 0.5 c  $\hat{i}$ (where c is the velocity of light). The ratio of the force acting on charge q1 to q2 is:

16 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Force on q₁ :

$F_{q_{1}} = q (V \times B) = 4 π (0.5 c \hat{i}) \times \frac{B_{0}}{\sqrt[]{2}} (c o s (k z - ω t) \hat{i} + c o s (k z - w t) \hat{j})$

$= 4 π (0.5 c) (\frac{B_{0}}{\sqrt[]{2}}) c o s (k \frac{π}{k}) \hat{k}$

For on q₂:

= $2 π (0.5 c) (\frac{B_{0}}{\sqrt[]{2}}) c o s (k \frac{3 π}{k}) \hat{k}$

So ratio will be 2 : 1

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New answer posted•a year ago

Electromagnetic Waves Class 12th

Electric field in a plane electromagnetic wave is given by

E = 50 sin(500x – 10 × 10¹⁰t) V/m

The velocity of electromagnetic wave in this medium is:

(Given C = speed of light in vacuum)

13 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

$V = \frac{c o e f f i c i e n t o f t i m e}{c o e f f i c i e n t o f x} = \frac{ω}{k}$

$\Rightarrow V = \frac{10 \times 1 0^{10}}{500} = 2 \times 1 0^{8} = \frac{2 \times c}{3}$

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New answer posted•a year ago

Electromagnetic Waves Class 12th

If E and H represents the intensity of electric field and magnetizing field respectively, then the unit of E/H will be:

6 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

$\frac{E}{H} = \frac{V o l t / m e t r e}{A m p e r e / m e t r e} = \frac{V o l t}{A m p e r e} = o h m$

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