Electromagnetic Waves
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8.9 The terminology of different parts of the electromagnetic spectrum is given in the text. Use the formula E = h (for energy of a quantum of radiation: photon) and obtain the photon energy in units of eV for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation?
8.9 The terminology of different parts of the electromagnetic spectrum is given in the text. Use the formula E = h (for energy of a quantum of radiation: photon) and obtain the photon energy in units of eV for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation?
8.9 Energy of a photon is given as:
E = h = , where
h = Planck’s constant = 6.6 Js
c = Speed of light = 3 m/s
= wavelength of radiation
Hence, E = J = J = eV = eV
The following table lists the photon energies for
8.8 Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is = 50.0 MHz
(a) Determine, B0, , k, and .
(b) Find expressions for E and B.
8.8 Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is = 50.0 MHz
(a) Determine, B0, , k, and .
(b) Find expressions for E and B.
8.8 Electric field amplitude, = 120 N/C
Frequency of source, = 50 MHz = 50 Hz
Speed of light, c = 3 m/s
Magnitude of magnetic field strength is given as
= = 4 T = 400 T = 400 nT
= 2 = 2 &n
8.7 The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?
8.7 The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?
8.7 The amplitude of magnetic field of the electromagnetic wave in a vacuum,
= 510 nT = 510 T
Speed of the light in vacuum, c = 3 m/s
Amplitude of electric field of the electromagnetic wave is given by the relation,
E = c = 3 510 N/C = 153 N
8.6 A charged particle oscillates about its mean equilibrium position with a frequency of 109 Hz. What is the frequency of the electromagnetic waves produced by the oscillator?
8.6 A charged particle oscillates about its mean equilibrium position with a frequency of 109 Hz. What is the frequency of the electromagnetic waves produced by the oscillator?
8.6 The frequency of an electromagnetic wave produced by the oscillator is the same as that of a charged particle oscillating about its mean position, i.e. Hz.
8.5 A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?
8.5 A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?
8.5 The lowest tuning frequency = 7.5 MHz = 7.5 Hz
The highest tuning frequency = 12 MHz = 12 Hz
Speed of light, c = 3 m/s
The wavelength for lowest tuning frequency, = = = 40 m
The wavelength for highest tuning freq
8.4 A plane electromagnetic wave travels in vacuum along z-direction. What can you say about the directions of its electric and magnetic field vectors? If the frequency of the wave is 30 MHz, what is its wavelength?
8.4 A plane electromagnetic wave travels in vacuum along z-direction. What can you say about the directions of its electric and magnetic field vectors? If the frequency of the wave is 30 MHz, what is its wavelength?
8.4 The electromagnetic wave travels in a vacuum along the z- direction. The electric field (E) and the magnetic field (H) are in the x-y plane. They are mutually perpendicular.
Frequency of the wave, = 30 MHz = 30 /s
Speed of light in vacuum, c = 3 m/s
Wavelength
8.3 What physical quantity is the same for X-rays of wavelength 10–10 m, red light of wavelength 6800 Å and radio waves of wavelength 500m?
8.3 What physical quantity is the same for X-rays of wavelength 10–10 m, red light of wavelength 6800 Å and radio waves of wavelength 500m?
8.3 The speed of light (3 m/s) in a vacuum is the same for all wavelengths. It is independent of the wavelength in the vacuum.
8.2 A parallel plate capacitor (Fig. 8.7) made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad s–1.
(a) What is the rms value of the conduction current?
(b) Is the conduction current equal to the displacement current?
(c) Determine the amplitude of B at a point 3.0 cm from the axis between the plates.

8.2 A parallel plate capacitor (Fig. 8.7) made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad s–1.
(a) What is the rms value of the conduction current?
(b) Is the conduction current equal to the displacement current?
(c) Determine the amplitude of B at a point 3.0 cm from the axis between the plates.

8.2 Radius of each circular plate, R = 6.0 cm = 0.06 m
Capacitance of parallel capacitor, C = 100 pF = 100 F
Supply voltage, V = 230 V
Angular frequency, = 300 rad/s
rms value of the conduction current, I = , where
Hence, I = V = 230 100 = 6
8.1 Figure 8.6 shows a capacitor made of two circular plates each of radius 12 cm, and separated by 5.0 cm. The capacitor is being charged by an external source (not shown in the figure). The charging current is constant and equal to 0.15A.
(a) Calculate the capacitance and the rate of change of potential difference between the plates.
(b) Obtain the displacement current across the plates.
(c) Is Kirchhoff’s first rule (junction rule) valid at each plate of the capacitor? Explain.

8.1 Figure 8.6 shows a capacitor made of two circular plates each of radius 12 cm, and separated by 5.0 cm. The capacitor is being charged by an external source (not shown in the figure). The charging current is constant and equal to 0.15A.
(a) Calculate the capacitance and the rate of change of potential difference between the plates.
(b) Obtain the displacement current across the plates.
(c) Is Kirchhoff’s first rule (junction rule) valid at each plate of the capacitor? Explain.

8.1 Radius of the each circular plate, r = 12 cm = 0.12
Distance between the plates, d = 5 cm = 0.05 m
Charging current, I = 0.15 A
Permittivity of free space, = 8.85
Capacitance between two plates is given by the relation,
C = , where A = Area of each plate = =
C = = 8.007
F
Charge
How do electromagnetic waves propagate in space without a medium?
How do electromagnetic waves propagate in space without a medium?
Electromagnetic waves do not require a medium to propagate because they generate self-sustaining oscillations of magnetic and electric fields. Hence, it can travel through the vacuum of space. A changing magnetic field generates an electric field and vice versa. This property allows the wave to carr