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New answer posted
a year agoContributor-Level 6
In order to seek admissions under a B.E. / B.Tech course at Pandit Dev Prabhakar Shastri College of Technology (PDSCT), one will have to confirm on the eligibility criteria that is the passing of 10+2 in the physics, chemistry, and mathematics subjects that should have been at least with 50 percent aggregate marks. The admission can be done most of the time on the basis of the scores of the national or state level entrance test such as JEE Main or MP BE. Upon successful sitting of the respective entrance exam, the candidates are to log on to the official PDSCT site to make the application in the online application form, the subsequent
New answer posted
a year agoContributor-Level 10
During the IIITDM Kancheepuram placements M.Tech in 2025, the highest package offered to M.Tech CSE branches stood at INR 18.78 LPA. Check out the key highlights of M.Tech placements for 2025 tabulated below:
| Particulars | MTech Placement Statistics (2025) |
|---|---|
| the highest package | INR 18.78 LPA |
| Average Package | INR 10.20 LPA |
| No. of offers | 14 |
New answer posted
a year agoContributor-Level 6
In PDSCT, the JEE Main cutoff is different in the specialisation and category of B.E./B.Tech courses. The last rank in B.E Computer Science and Engineering and Information Technology in 2024 was 1067666 and 1246772 correspondingly for B.E Computer Science and Engineering and B.E Information Technology when applied by the General Home State candidates. These cutoffs provide the indication of the necessary JEE Main grades for admission.
New answer posted
a year agoContributor-Level 10
The highest package offered to the M.Tech CSE branch stood at INR 18.8 LPA. Check out the placement details for M.Tech branch-wise packages for the batch passing out in 2025 from the table below:
| Branch | No. of Offers (2025) | Offer Percentage (2025) | Highest Package (2025) |
|---|---|---|---|
| CSE (DS &AI) | 8 | 72.7% | INR 18.78 LPA |
| ECE (VLSI) | 3 | 75% | INR 18.78 LPA |
| ECE (CSD) | 1 | 50% | INR 6 LPA |
| SM | 1 | 50% | INR 15 LPA |
| ESD | 1 | 505 | INR 6 LPA |
New answer posted
a year agoBeginner-Level 1
At JECRC College, admissions are taken through REAP (Rajasthan Engineering Admission Process) counselling.The selection is based on JEE Main marks — the higher your JEE score, the better your chances of getting your preferred branch in the counselling process. So if you have a pecentile above 85 then you have higher chances of selection ( cutoff varries according to caste category).But that 60% criteria is for overall class 12th marks.
New answer posted
a year agoContributor-Level 6
To take admission to B.E. / B.Tech course at Pandit Dev Prabhakar Shastri College of Technology (PDSCT), a student should have passed 10+2 with Physics, Chemistry, and Mathematics subjects and minimum aggregate marks of 50% (45% of the general category). The choice is largely determined on the grounds of valid admission scores on national/state level entrance test such as JEE Main, MP BE, or MPPET.
New answer posted
a year agoContributor-Level 10
The JEE Main result date for Naraina College of Engineering and Technology (NCET), Kanpur corresponds to the national JEE Main Session 2 result. According to several admission timeline listings, including those for this college, the Session 2 JEE Main result was declared on April 19, 2025
JEE Main Session 2 exam dates: April 2–9, 2025
Result declared: April 19, 2025
New answer posted
a year agoContributor-Level 9
JEE Main ranks are required for admission to BTech. courses at the Government Engineering College, Patan. The ranks for admission in 2025 varied from 901126 to 990423 based on different rounds, the category to which the student belongs, and the specialisation of BTech in which the student is interested. You can find the detailed cutoff on: Government Engineering College, Patan Cutoff 2025 (Out): Check GUJCET Round Wise Ranks.
New answer posted
a year agoContributor-Level 9
In order to secure admission in B.E./B.Tech in BITS Gwalior, you should pass 12th class with Maths, Chemistry, and Physics, securing at least 45% marks (40% for reserved category of MP).
You should appear in JEE Main or MP entrance exam.
Then you can apply via the official counselling process. Diploma holders can apply for direct second-year admission.
New answer posted
a year agoContributor-Level 10
To gain admission into Naraina College of Engineering and Technology (NCET), Kanpur for a B.E./B.Tech program, follow these steps:
Check Eligibility:Complete 10+2 (or equivalent) with Physics, Mathematics, and one of Chemistry/Biotech/Biology/Technical Vocational subjects.
Minimum 45% marks (general/OBC/EWS); 40% for SC/ST categories.
Appear for Qualifying Entrance Exams
Acceptable scores:JEE Main
UPTAC (UP B.Tech Admission Counselling)
Approximately 75% seats via UPTAC, 10% via JEE Main merit, and 15% through management quota.
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