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New answer posted
2 weeks agoContributor-Level 10
Yes, you can get admission at this institute with a GUJCET rank of 40000 if you belong to the OBC HS quota.
For this category, the last round cutoff rank ranged from 33867 to 50893. Hence, admission to this institute is possible, but only to two courses. To know which, refer to the table below.
| Course | LDRP Institute of Technology and Research GUJCET cutoff 2025 |
|---|---|
| B.E. in Information Technology | 50795 |
| B.E. in Computer Engineering | 50893 |
New answer posted
2 weeks agoContributor-Level 10
The highest rank overall to get into the LDRP Institute of Technology and Research was 50893. This was the cutoff rank for the OBC HS quota.
To know the highest cutoff rank for other courses, students can see the list below.
- General: 50795
- SC: 38845
- EWS: 50565
- ST: 31081
For more details, students can click here.
New answer posted
2 weeks agoContributor-Level 10
LDRP Institute of Technology and Research BE cutoff 2025 for the OBC HS quota ranged from 35209 to 50893 for various BE courses.
In the last round, the most and least sought-after courses were B.E. in Electronics and Communication Engineering and B.E. in Computer Engineering, respectively. To know the first and last round cutoff for these and other courses, see the table below.
| Course | Round 1 (Closing Rank) | Last Round (Closing Rank) |
|---|---|---|
| B.E. in Electronics and Communication Engineering | 35209 | 33867 |
| B.E. in Mechanical Engineering | 36051 | 36051 |
| B.E. in Information Technology | 36056 | 50795 |
| B.E. in Computer Engineering | 36632 | 50893 |
New answer posted
2 weeks agoContributor-Level 10
LDRP Institute of Technology and Research BTech cutoff 2025 was released for various Home State categories for the BE course.
For the General HS quota, the overall cutoff ranged from 19600 to 50795. Students can refer to the table below to know the first and last round cutoff for all courses for this category.
| Course | Round 1 (Closing Rank) | Last Round (Closing Rank) |
|---|---|---|
| B.E. in Civil Engineering | 36972 | 50769 |
| B.E. in Computer Engineering | 22713 | 36919 |
| B.E. in Electronics and Communication Engineering | 19600 | 24683 |
| B.E. in Electrical Engineering | 35655 | 50654 |
| B.E.2 in Information Technology | 28685 | 50795 |
| B.E. in Mechanical Engineering | 30894 | 38364 |
Note: Other categories will have different cutoffs accordingly.
New answer posted
2 weeks agoContributor-Level 10
No, if you belong to the OBC HS quota, you cannot get admission to this college with a GUJCET rank of 40000. To be eligible for admission, OBC HS students needed to have a rank of at least 35651 to be considered for enrollment in any BTech course.
Students can refer to the table below to know the last round cutoff for all courses, and what is the highest rank required for each. (Sorted from most to least competitive).
| Course | Sarvajanik College of Engineering and Technology GUJCET cutoff 2025 |
|---|---|
| B.Tech. in Artificial Intelligance and Data Science | 11914 |
| B.Tech. in Computer Science | 13471 |
| B.Tech. in Electronics and Communication Engineering | 16998 |
| B.Tech. in Information Technology | 17098 |
| B.Tech. in Instrumentation and Control Engineering | 28156 |
| B.Tech. in Civil Engineering | 31592 |
| B.Tech. in Mechanical Engineering | 33652 |
| B.Tech. in Chemical Engineering | 34354 |
| B.Tech. in Electrical Engineering | 35651 |
New answer posted
2 weeks agoContributor-Level 10
Sarvajanik College of Engineering and Technology GUJCET cutoff 2025 was released for admission to several BTech courses, with BTech CSE being one of them.
For the General HS quota, the overall cutoff ranged from 5154 to 6301. Hence, students who belong to this category had to attain a rank of at least 6301 to be considered for admission.
To know the cutoff range for other categories, see the table below.
| Category | Sarvajanik College of Engineering and Technology BTech cutoff 2025 |
|---|---|
| OBC | 13199 - 13471 |
| SC | 27749 - 33580 |
| EWS | 5749 - 7674 |
| ST | 32897 - 32897 (R1) |
New answer posted
2 weeks agoContributor-Level 10
Sarvajanik College of Engineering and Technology BTech cutoff 2025 for the OBC category students belonging to the Home State quota ranged from 13199 to 35651 for several BTech courses.
In the first round, BTech CSE was the most competitive course, with a cutoff of 13199, and in the last round, BTech in Artificial Intelligence and Data Science turned out to be the most competitive, with a cutoff of 11914.
Students can refer to the table below to know the first and last round cutoff for various other courses for this category.
| Course | Round 1 (Closing Rank) | Last Round (Closing Rank) |
|---|---|---|
| B.Tech. in Civil Engineering | 36196 | 31592 |
| B.Tech. in Electronics and Communication Engineering | 20123 | 16998 |
| B.Tech. in Computer Science | 13199 | 13471 |
| B.Tech. in Chemical Engineering | 34467 | 34354 |
| B.Tech. in Electrical Engineering | 30341 | 35651 |
| B.Tech. in Information Technology | 16219 | 17098 |
| B.Tech. in Instrumentation and Control Engineering | 27988 | 28156 |
| B.Tech. in Mechanical Engineering | 36334 | 33652 |
| B.Tech. in Artificial Intelligance and Data Science | 15462 | 11914 |
New answer posted
2 weeks agoContributor-Level 10
Sarvajanik College of Engineering and Technology GUJCET cutoff 2025 was released for admission to the BTech course for various Home State quota categories.
For the General HS category, the overall cutoff ranged from 5154 to 36084, wherein the most sought-after course was B.Tech. in Computer Science, with the first round cutoff of 5154, and the last round cutoff of 6301.
To know the cutoff range for other categories, see the list below.
- OBC: 13199 - 35651
- SC: 23740 - 50439
- EWS: 5749 - 38361
- ST: 25264 - 37664
New answer posted
2 weeks agoContributor-Level 10
With your OBC-NCL category rank of 2,69,901 and domicile of Madhya Pradesh, admission to CSE or its specializations at MITS Gwalior or SATI Vidisha is not possible. The closing ranks for CSE at these colleges are much lower (within ~1–1.5 Lacs for OBC-NCL home-state candidates). At your rank, only lower-demand branches (Civil, Mechanical, Electrical) may be available.
Cutoff Data (2025 – Home State, OBC-NCL)
MITS Gwalior (via MP DTE Counseling)
- CSE: Closing rank ~1,08,686 (Round 2)
- CSE Specializations (AI/ML, Data Science, IT, CS & Design): Closing ranks ~1.2–1.5 lakh
- Other branches (ECE, Mechanical, Civil): Extend u
New answer posted
2 weeks agoContributor-Level 10
With your current JEE Main rank (~4,00,510), admission to CSE in top government colleges of Delhi/NCR (like IIT Delhi, DTU, NSUT, IIIT Delhi, NIT Delhi) is not possible. However, you can secure B.Tech CSE admission in private universities and affiliated colleges in Delhi/NCR through direct admission or state-level counseling.
Delhi/NCR B.Tech CSE Admission Landscape
Government/Public Institutions (Require Strong JEE Rank)
- IIT Delhi, DTU, NSUT, IIIT Delhi, NIT Delhi, Jamia Millia Islamia
- Cutoffs for CSE are well below 25,000–30,000 ranks.
- Your rank (4 lakh+) is far beyond cutoff → not eligible.
Private Universities & Colleges
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