Equilibrium
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5 months agoContributor-Level 10
(a) On increasing the volume of the container, the vapour pressure will initially decrease because the same amount of vapours is now distributed over a larger space.
(b) On increasing the volume of the container, the rate of evaporation will increase initially because now more space is available. Since the amount of the vapours per unit volume decrease on increasing the volume, therefore, the rate of condensation will decrease initially.
(c) Finally, equilibrium will be restored when the rates of the forward and backward processes become equal. However, the vapour pressure will remain unchanged because it depends upon the tempera
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5 months agoContributor-Level 10
KC= [SO3]2 / [SO2]2 [O2]
= (1.90)2 / (0.60)2 (0.82)
= 12.229 L mol-1
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