Equilibrium

Get insights from 241 questions on Equilibrium, answered by students, alumni, and experts. You may also ask and answer any question you like about Equilibrium

  • 241

    Questions

  • 0

    Discussions

  • 0

    Active Users

  • 0

    Followers

Have a question about Equilibrium? Ask our experts

Ask Your Question

Keep it short & simple. Type complete word. Avoid abusive language.

New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

(a) In case of a non-polar (covalent) solvent, solvation enthalpy is small and hence, not sufficient to overcome lattice enthalpy of the salt. Consequently, the salt does not dissolve in non-polar solvent. As a general rule, for a salt to be able to dissolve in a particular solvent its solvation en

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

(d) Higher order ionization constants (Ka2, Ka3) are smaller than the lower order ionization constant (Ka1) of a polyprotic acid. The reason for this is that it is more difficult to remove a positively charged proton from a negative ion due to electrostatic forces. This can be seen in the case of r

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

(c) Ammonium hydroxide is a weak base (Kb = 1.77 * 10–5) and not a weak acid. Therefore, it remains almost unionised in solution. This results in increased of H+ ion concentration in solution making the solution acidic. Thus, the pH ofNH4Cl solution in water is less than 7.

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

(a) The cations (e.g., Na+, K+, Ca2+, Ba2+, etc.) of strong bases and anions (e.g., Cl–, Br–, NO3–, ClO4– etc.) of strong acids simply get hydrated but do not hydrolyse, and therefore the solutions of salts formed from strong acids and bases are neutral i.e., their pH is 7. However, the other categ

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

(b) Both are correct statements but R is not the reason for A. The acid-base pair that differs only by one proton is called a conjugate acid-base pair. Therefore, OH– is called the conjugate base of an acid H2O and NH4+ is called conjugate acid of the base NH3. If Brönsted acid is a strong acid the

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

For precipitation to take place, it is required that the calculated ionic product exceeds the Ksp value. So, following data on Ksp values should have been provided to answer the question.

KspforFeS=6.3×10−18,

MnS=2.5×10−13,

ZnS=1.6×10−24

CdS=8.0×10−27

Before mixing:

[S2−]=1.0×10−19M and [M2+]=0.04M&nbs

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

CaSO4 (s)↔Ca2+ (aq)+SO2−4 (aq)

Ksp= [Ca2+] [ SO2−4]

Let the solubility of CaSO4 be s.

[Ca2+] = [ SO2−4] = s

Then, Ksp=s2

9.1×10−6=s2

s =3.02×10−3mol/L

Molecular mass of CaSO4=136g/mol

Solubility of CaSO4 in gram/L= 3.02×10−3×136=0.41g/L

This means that we need 1L of water to dissolve 0.41g of CaSO4.

Therefor

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

Let the maximum concentration of each solution be x mol/L. After mixing, the volume of the concentrations of each solution will be reduced to half i.e., x/2.

∴ [FeSO4]= [Na2S]=x / 2

Then, [Fe2+]= [FeSO4]=x/ 2

Also, [S2−]= [Na2S]=x/2

FeS (x)↔Fe2+ (aq)+S2− (aq)

Ksp= [Fe2+] [S2−]

= >6.3×10−18= (x/2) (x/2)

x2/

...Read more

Thumbs Up IconUpvote Thumbs Down Icon