Hindi

The 2025 main exam results of CBSE Class 10 th and 12 th were declared in May 13, 2025. Students who have made an application to re-evaluate or re-verify marks got their results of Class 12th Re-evaluation/ Verification (Lot 1) published on July 17, 2025. The CBSE is also told to publish the Class 10th and 12th Supplementary Examination Results 2025 in the first week of August 2025 which could arrive somewhere towards 5 August. This outcome can be located on state portals such as cbseresults.nic.in and cbse.gov.in.

Yes, you can study Philosophy in Hindi. Many universities and colleges offer Philosophy degree courses in Hindi medium at BA and MA levels. Apart from this, you can also explore Philosophy in Hindi courses from distance colleges like IGNOU.

You can get NIOS Hindi question paper from previous examination including April 2025 primarily from the official NIOS website or other educational resource that host an NIOS papers

Yes, the Manohar Memorial College of Education (MMCE) does offer a B.Ed. program in Hindi. The course is a full-time, two-year program leading to a Bachelor of Education degree in Hindi. 

These are some of the institution that offers Bachelor courses having a subject combination of Hindi and English.

1. Delhi University and admision mode is CUET (expected cutoff for general catagory is 220-235)

2. Banaras Hindu University and admission mode is CUET (expected cutoff for general catagory (expected cutoff for general catagory is 200-220)

3. Punjab University and admission mode is CUET (expected cutoff for general catagory is 190-210)

4. Chandigarh University and admission is based on merit

sin (A + B) = sinA cosB + cosA sinB

sin (A - B) = sinA cosB - cosA sinB

cos (A + B) = cosA cosB - sinA sinB

cos (A - B) = cosA cosB + sinA sinB

tan (A + B) = (tanA + tanB) / (1 - tanA tanB)

tan (A - B) = (tanA - tanB) / (1 + tanA tanB) 

Double Angle Formulas:

sin 2? = 2 sin? cos?

cos 2? = cos²? - sin²? = 2cos²? - 1 = 1 - 2sin²?

tan 2? = 2 tan? / (1 - tan²? ) 

Triple Angle Formulas:

sin 3? = 3 sin? - 4 sin³?

cos 3? = 4 cos³? - 3 cos?

Yes sure you can get UGC net june 25 on Shiksha only.

Here is the link :-https://www.shiksha.com/exams/ugc-net-exam-mocktest

Kindly visit and appear for the mock test. You will know the score

Thank you 

The following are the minimum qualifying requirements for candidates who want to pursue this course:

• Students must have finished 10+2 from a recognised board and have chosen Hindi as a required language.
• Most institutions demand a minimum of 50% in their 10+2 exams. To be eligible for this programme, students must have a combined percentage of 45%.
• Candidates must have completed their 12th grade in arts.