IIT Roorkee - Indian Institute of Technology Cut-off
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New answer posted
a month agoContributor-Level 10
For students belonging to the General AI quota, most of the BTech branches remained open till the last round for admission at IIT Roorkee. The cutoffs of different branches vary across rounds and categories. Some of the BTech branches, such as CSE, ECE, Civil, and Mechanical, etc., reflected a rise in the last round, closing ranks as compared to initial rounds, indicating IIT Roorkee seats remained vacant till the last round for BTech admission. Whether the branch will remain open till the last round or not depends on the availability of seats allocated for each category. In the meantime, candidates can check out the round-wise cutoff
New answer posted
3 months agoContributor-Level 10
The IIT Roorkee UCEED cutoff 2025 was released for different categories of students belonging to the All India quota. The institute accepts the UCEED entrance exam, followed by counselling rounds for B.Des admission. For the General category students belonging to the AI quota, the UCEED last round closing rank stood at 111. The category-wise cutoff details for the last round are tabulated below:
Category | UCEED Cutoff 2025 (Last round closing rank) |
---|---|
General | 111 |
OBC | 56 |
SC | 33 |
ST | 12 |
EWS | 18 |
New answer posted
3 months agoContributor-Level 10
For IIT Roorkee B.Des admission, a UCEED rank of 75 is considered to be a good rank in the General AI category. In 2025, the IIT Roorkee UCEED cutoff ranged between 91 and 111. Therefore, candidates with a cutoff rank of 75 have high chances of getting a seat at this institute. Check out the table below to view the B.Des round-wise UCEED cutoff ranks for the General AI category students.
Round | UCEED Cutoff 2025 (General AI Quota) |
---|---|
1 | 91 |
2 | 96 |
3 | 104 |
4 | 105 |
5 | 111 |
New answer posted
3 months agoContributor-Level 10
IIT Roorkee UCEED cutoff 2025 concluded with the release of the Round 5 cutoff list. If you belong to the General AI quota, the last round closing rank for B.Des admission was 111. During Round 1 admission, the closing rank stood at 91 for the same category and quota. So, candidates seeking admission to the B.Des programme at IIT Roorkee must target to secure a cutoff rank of up to 111 or below. The cutoff ranks vary for different rounds and categories.
New answer posted
3 months agoContributor-Level 10
To get into IIT Roorkee, students must target to secure a maximum rank of up to 2556 for BTech admission if they belong to the General AI quota. The lower the cutoff rank, the higher the probability of getting the top BTech branch for admission. The required cutoff rank varies for different rounds, courses, specialisations and categories. Candidates can refer to the table below to view the IIT Roorkee branch-wise required cutoff in the last round for SC AI category students.
Course | JEE Advanced Cutoff 2025 (SC AI Quota) |
---|---|
B.Tech. in Computer Science and Engineering | 129 |
B.Tech. in Data Science and Artificial Intelligence | 213 |
B.Tech. in Electronics and Communication Engineering | 394 |
B.Sc. + M.Sc. in Mathematics and Computing | 569 |
B.Tech. in Electrical Engineering | 572 |
B.Tech. in Mechanical Engineering | 1039 |
B.Tech. in Chemical Engineering | 1333 |
B.Tech. in Energy Engineering | 1470 |
B.Tech. in Engineering Physics | 1540 |
B.Tech. in Civil Engineering | 1655 |
B.Tech. in Production and Industrial Engineering | 1717 |
B.Tech. in Metallurgical and Materials Engineering | 2026 |
Integrated B.Sc. + M.Sc. in Economics | 2176 |
B.Tech. Biosciences and Bioengineering | 2210 |
Integrated B.Sc. + M.Sc. in Physics | 2240 |
B.Sc. + M.Sc. in Chemical Sciences | 2318 |
Integrated M.Tech. in Geophysical Technology | 2486 |
Integrated M.Tech. in Geological Technology | 2556 |
Bachelor of Architecture (B.Arch.) | 3181 |
New answer posted
3 months agoContributor-Level 10
For CSE admission at IIT Roorkee, the JEE Advanced Round 4 closing rank was 555 for the students belonging to the OBC category under the AI quota. For the same specialisation and round, the closing rank was 481 in 2024, whereas in 2023, the cutoff rank stood at 405. Candidates seeking admission to BTech in CSE must target to secure a JEE Advanced rank of up to 550 or below. Please note that the cutoff ranks vary for different rounds, specialisations, and categories.
New question posted
4 months agoNew answer posted
a year ago
Contributor-Level 10
IIT Roorkee's latest cut off is an estimated cut off for M.Tech Artificial Intelligence. If you want to take admission in this college, then stay active on the official website of the college. From there you will get all the information about the college, complete and correct. We can only tell you an estimated cut off, so stay active on the official website. From there you will get the correct information.
New answer posted
a year agoContributor-Level 10
The IIT Roorkee JAM Cutoff 2024 is out for Round 5. The most competitive course is M.Sc in Applied Geology, with the Cutoff of 52, for the General AI category candidates. For the OBC AI category candidates, the Cutoff rank for M.Sc in Applied Geology is 109.
If the Cutoff rank is more than 232, there is no scope for admission to IIT Roorkee, for the General AI category candidates. However, candidates can get admission under the cutoff varied from 52 to 232 for the General AI category.
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New answer posted
a year agoBeginner-Level 4
Hello,
The Master of Design programme at IIT Roorkee is aimed at providing an engaging environment to foster creativity and skills through an interdisciplinary process of teaching and training.
MINIMUM ELIGIBILITY CRITERIA
Candidates belonging to General, GEN-EWS and OBC category must have secured at least 60% marks or CGPA of 6.00 on a 10-point scale at the qualifying degree level; Candidates belonging to SC/ST/PD category must have secured 55% or- S, 50 CGPA on a 10 point scale. The marks awarded for the qualifying degree will be considered.
For the general category, the 610-620 marks in gate 2024 can earn you mdes course in industrial d
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