JEE Main
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New answer posted
a year agoContributor-Level 9
B.Tech Electrical and Electronics Engineering
1171620 1196560
B.Tech Mechanical Engineering
1204183 1289410
B.Tech Electronics & Communication Engineering
1244503 1350177
B.Tech Civil Engineering
1333580 1350110
B.Tech Artificial Intelligence and Machine Learning
1394458 1411917
B.Tech Data Science
1403607 1411166
B.Tech Information Technology
1404004 1083289
B.Tech Computer Science Engineering
1406366 1376800
B.Tech Artificial Intelligence and Data Science
1413575 1404481
New answer posted
a year agoContributor-Level 6
In PDSCT, the JEE Main cutoff is different in the specialisation and category of B.E./B.Tech courses. The last rank in B.E Computer Science and Engineering and Information Technology in 2024 was 1067666 and 1246772 correspondingly for B.E Computer Science and Engineering and B.E Information Technology when applied by the General Home State candidates. These cutoffs provide the indication of the necessary JEE Main grades for admission.
New answer posted
a year agoContributor-Level 10
The JEE Main result date for Naraina College of Engineering and Technology (NCET), Kanpur corresponds to the national JEE Main Session 2 result. According to several admission timeline listings, including those for this college, the Session 2 JEE Main result was declared on April 19, 2025
JEE Main Session 2 exam dates: April 2–9, 2025
Result declared: April 19, 2025
New answer posted
a year agoContributor-Level 9
JEE Main ranks are required for admission to BTech. courses at the Government Engineering College, Patan. The ranks for admission in 2025 varied from 901126 to 990423 based on different rounds, the category to which the student belongs, and the specialisation of BTech in which the student is interested. You can find the detailed cutoff on: Government Engineering College, Patan Cutoff 2025 (Out): Check GUJCET Round Wise Ranks.
New answer posted
a year agoContributor-Level 10
Yes, it is important that the BTech aspirants have a valid score of JEE Main. NIT Srinagar grants admission based on merit in this entrance score only. The specialisation-wise cutoff is released as per merit in the entrance examination. For seat allotment, the aspirants rank is taken into consideration. Hence, the aspirants must appear for the national-level exam and secure a good rank.
New answer posted
a year agoContributor-Level 9
JEE Main ranks are required for admission to BTech courses at the Radharaman Institute of Technology and Science. The ranks for admission in 2023 varied from 748320 to 1034264 based on different rounds, the category to which the student belongs, and the specialisation of BTech in which the student is interested.
New answer posted
a year agoContributor-Level 8
Admission to TIT&S B.Tech requires 10+2 with PCM and a valid JEE Main or MP-PET score, followed by seat allocation through MP DTE counselling . There is no direct or management quota route bypassing entrance exam norms—admission is purely based on merit via the centralized process . Diploma holders can enter laterally into 2nd year through the same counselling mechanism . In short: JEE Main or MP-PET score + DTE counselling is mandatory—no entrance bypass allowed.
New answer posted
a year agoContributor-Level 10
The JEE main result date for feroze gandhi Institute of Engineering and Technology like all other participating institution artificially announced by NTA National test agency on the official website JEE main JEE main nta.nic.in the result for session 2 were released on 29 April 2025 candidates can check the result by login in their application number and date of birth or password on the website
New answer posted
a year agoContributor-Level 10
During the Sardar Patel Institute of Technology BE/BTech cutoff 2024, the last-round closing ranks ranged between 8307 and 16209 for the General AI category students. Of all the BE/BTech specialisations, the one that faced fierce competition was B.Tech. in Computer Science and Engineering (Artificial Intelligence and Machine Learning). The first round cutoff rank for the same stood at 8095.
New answer posted
a year agoContributor-Level 10
Result for Sardar Vallabhbhai Patel Institute of Technology at typically released on the same date as the overall JEE main result as SVIT vasad admission are based on JEE Mains score the JEE main session 2 result were announced on May 23 2025 for candidates who appeared in both session the final result is prepared based on normalized score from both attempt
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