JEE

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6 months ago

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New question posted

6 months ago

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New answer posted

6 months ago

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R
Ranjeeta Rai

Contributor-Level 10

Manipur University offers BTech via its affiliated college, Manipur Institute of Technology. For admission to the BTech course, a JEE Main score is required to get shortlisted. However, candidates are also provided with the option of applying for the BTech course without a JEE score. Candidates who are applying under the Non-JEE category, an entrance test conducted for the remaining seats that are not filled by the candidates with a JEE (Main) 2025 score card.  

New question posted

6 months ago

0 Follower 4 Views

New answer posted

6 months ago

0 Follower 2 Views

K
Kavya Gogia

Contributor-Level 10

Yes, admission to Arunodaya University's B.Tech programme can be obtained without the JEE Main or JEE Advanced scores. Arunodaya University generally accepts applications based on merit in the qualifying examination (Class 12).

New answer posted

6 months ago

0 Follower 6 Views

M
Manan Patel

Beginner-Level 5

With an OBC rank of 44,254 and a CRL rank of 133,700, you might have a shot at getting into some of the lower-ranked NITs or IIITs for a B.Tech program. Your chances are likely better for less competitive branches like Civil, Chemical, or Mechanical Engineering at these institutions.

New answer posted

6 months ago

0 Follower 22 Views

M
Manan Patel

Beginner-Level 5

If your JEE Mains rank is around 5 lakhs, you might want to look into state-level colleges or private institutions for a B.Tech in Computer Science Engineering (CSE). Unfortunately, getting into National Institutes of Technology (NITs) and other top government colleges could be a stretch at that rank, especially for the highly sought-after CSE program.

New answer posted

6 months ago

0 Follower 5 Views

E
Esha Garg

Beginner-Level 5

Yes,  NCERT Solutions for Class 11 Straight Lines are very useful for JEE and other competitive exams.  NCERT Straight Lines are designed for developing fundamental concepts such as general equation, equation of slope, equation of slope, mid point and others, which form the backbone of many advanced problems in exams like JEE Main and Advanced.

The Shiksha's NCERT Solutions provides step-by-step explanations to help students in logical problem-solving techniques. Students can build the conceptual strength and formula fluency required to tackle higher-level problems found in books like Cengage or previous year question pap

...more

New answer posted

6 months ago

0 Follower 26 Views

N
Nishant Agarwal

Contributor-Level 9

With an 89 percentile in JEE Mains and 981 marks in your intermediate exams, you are eligible for admission to the CSE branch at SASTRA University. The admission is based on a combined score of JEE (25% weightage) and 12th-grade marks (75% weightage). Your academic performance gives you a good chance of securing a seat.

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