JEE

Yes, you will get CSE at MBM Jodhpur.

If your CRL rank is below 55k-60k, then you can get CSE at MBM, which means around the 95-96 percentile is required.

The EM wave speed in a vacuum is determined by the permeability and permittivity of free space. It is given by the formula:

$c=\frac{1}{\sqrt{?0_{}?0_{}}}$

The constant value is around $3*{10}^8\text{ m/s.}$

This speed forms the basis for many scientific and technological applications. It is a fundamental physical constant.

The electric field (E) and magnetic field (B) in an electromagnetic wave are always perpendicular to each other and to the direction of wave propagation. The EM waves are transverse in nature. When the EM waves are moving along the X-axis, then along the y-axis, the electric field may oscillate and

Maxwell introduced the displacement current which ensures that when the conduction current is absent, the current continues in the circuits, such as in the capacitors. The displacement current plays a significant role in the derivation of electromagnetic waves. It shows that an electric field that i

Hello! With a JEE rank around 8.2 lakh, it might be tough to get into top-tier government colleges, but don't worry—you still have good private college options for B.Tech in CSE with decent placements. You can consider:

• Lovely Professional University (LPU)

• Chandigarh University

• Amity University (Noida)