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a year agoNew answer posted
a year agoBeginner-Level 4
You stand a good chance of being accepted into prestigious NITs. Candidates should aim for a JEE score of 250 in order to be admitted to NIT. A 90 percentile or higher can lead to admissions to prestigious NITs like NIT Delhi and NIT Calicut. Even lower ranks—70,000 and above—can get you into less well-known NITs, such the NITs in Sikkim and Meghalaya.
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a year agoNew answer posted
a year agoContributor-Level 9
The Qualifying cutoff marks for B.Ed in JEE to get shortlisted for Inmantec Institute is to get 350+ marks with 50% of the 12th grade.
B.Ed JEE Cut Off Marks 2024 determines if a candidate is eligible for admission to the 2-year B.Ed programme.
ST/SC candidates have a 5 % reservation for the B.Ed. JEE at Inmantec Institute.
Therefore, a candidate cannot join Inmantec Institutions without U.P. B.Ed. JEE for B.Ed.
New answer posted
a year agoContributor-Level 6
Biju Patnaik University of Technology (BPUT), Rourkela, Odisha offers various UG and PG courses in various disciplines such as architecture, engineering, management, pharmacy etc. B.Tech is one of the popular course here. They take admission through JEE Main or OJEE Main rank. Candidates should have passed their 12th exam from Science stream with physics, mathematics, chemistry/ biotechnology language or any other subject with a decent marks from a recognised board.
BPUT JEE Main cutoff 2022 for general category is between 214106 - 1506891. So, with your rank in JEE Main with OBC category you can easily take admission in the core
New answer posted
a year agoContributor-Level 10
Hi Aryan,
The last rank to be allocated in JEE 2023 by JoSAA counselling was 42,135. The cut-off was for the Indian Institute of Information Technology Manipur to enrol in the Electronics and Communication Engineering course.
I hope it will help.
Thank You.
New answer posted
a year agoContributor-Level 10
Hello Nandhu!
I have calculated the JEE Mains score basis on the percentile. The formula used is (100 - P)/100) * N + 1, where P is the percentile and N is the total number of students.
After the calculation based on your percentile, 50 - 60 out of 300 can be the possible score.
I hope it will help. You can reach out to us for further queries.
Thank You.
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