Kirchhoffs Law

Potential difference across 2k $\Omega$  is 5V, thus current through it,

$i=\frac{5}{2*10^3}=25*10^{-4}A.$           

If you want the Current Electricity Class 12 important questions, then check the Class 12 Physics previous year question paper pdf. Also, focusing on the Class 12 Physics past 5 years of exam questions to identify the current electricity class 12 important questions. Well, we have framed all the important questions in the NCERT Physics Class 12 Current Electricity solution pdf, which you can easily download through this article.

Class 12 Physics Chapter 3 Current Electricity is important for the board exam. The weightage of the chapter is 8-10%. When you practice the Current Electricity class 12 NCERT solutions, you get an overview of your preparation. If you are lacking in any concept, then it helps to build the conceptual knowledge.

The topics focused on while preparing the Current Electricity NCERT solutions are:

• Ohm's law

• Drift velocity

• Resistivity vs temperature

• Combination of cells

• Kirchhoff's rules and 

• Wheatstone bridge

Let us assume the potential at A = V_A = 0.
Now at junction C, according to KCL
i? + i? = i?
1 A + i? = 2 A

i? = 2 A
Now analyse potential along ACDB
V_A + 1 + i? (2) - 2 = V_B
0 + 1 + 2 (1) - 2 = V_B
V_B = 3 - 2
V_B = 1amp.