Logical Reasoning

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New answer posted

3 months ago

Natural gas once extracted from a source is purified for commercial use at natural gas plants. From gas plants it is pumped to various destinations through pipelines. There are pumping stations, at intermediate places to maintain recommended pressure in the pipelines. The pumping stations do not produce or process any natural gas. They pump out exactly the quantity they receive from plants or other pumping stations.

The following figure depicts a network gas pipelines. The circles denote the locations of gas plants, pumping stations or cities with big demand for natural gas. One location can be only one of these there. The numbers on t

...more
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P
Payal Gupta

Contributor-Level 10

From the figure and the conditions R can receive only 6 units (5 + 1) of natural gas if utilization is 100 Percent

New question posted

3 months ago

Natural gas once extracted from a source is purified for commercial use at natural gas plants. From gas plants it is pumped to various destinations through pipelines. There are pumping stations, at intermediate places to maintain recommended pressure in the pipelines. The pumping stations do not produce or process any natural gas. They pump out exactly the quantity they receive from plants or other pumping stations.

The following figure depicts a network gas pipelines. The circles denote the locations of gas plants, pumping stations or cities with big demand for natural gas. One location can be only one of these there. The numbers on t

...more
0 Follower 1 View

New answer posted

3 months ago

Direction for question: Answer the questions yon the basis of the information given below.

Natural gas once extracted from a source is purified for commercial use at natural gas plants. From gas plants it is pumped to various destinations through pipelines. There are pumping stations, at intermediate places to maintain recommended pressure in the pipelines. The pumping stations do not produce or process any natural gas. They pump out exactly the quantity they receive from plants or other pumping stations.

The following figure depicts a network gas pipelines. The circles denote the locations of gas plants, pumping stations or cities wit

...more
0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

From the figure the maximum quantity of natural gas that S can receive = 6 + 2 + 9 = 17 units.

New answer posted

3 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

 

Mohit

Manohar

Prashant

Dinesh

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New answer posted

3 months ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

 

Mohit

Manohar

Prashant

Dinesh

Round – 4

3200

3200

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3200

Round – 3

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Round – 2

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Initially

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New answer posted

3 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

 

Mohit

Manohar

Prashant

Dinesh

Round – 4

3200

3200

3200

3200

Round – 3

1600

1600

1600

1600

Round – 2

800

800

7200

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Round – 1

400

6800

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Initially

6600

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1800

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New answer posted

3 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

 

Mohit

Manohar

Prashant

Dinesh

Round – 4

3200

3200

3200

3200

Round – 3

1600

1600

1600

1600

Round – 2

800

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7200

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Round – 1

400

6800

3600

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Initially

6600

3400

1800

1000

New answer posted

3 months ago

Direction for questions: Answer the questions on the basis of the information given below.

In a school when a survey is conducted on liking of subjects out of three subjects physics, chemistry mathematics then outcome is as follow.

Total number of students who like physics, chemistry and mathematics is 30, 40, 50 respectively. 10 students shown interest in all three subjects, Number of students who like physics and mathematics both is equal to number of students who like chemistry and mathematics both and is equal to 3/4 times number of students who like physics and chemistry both 15 students like only chemistry.

When class teacher saw

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P
Payal Gupta

Contributor-Level 10

From the given condition g = 10,

Number of students who like both Physics and Maths = 10 + f

Number of students who like both chemistry and Maths = 10 + e

From given condition 10 + f = 10 + e or e = f

Similarly from 3rd condition ¾ (10 + e) = 10 + d

Or 30 + 3e = 40 + 4d

Or

d = 3e - 10/4

 Since 15 students like only chemistry hence b = 15

Number of students who like only chemistry is 40

Hence e + g + d + b = 40

or e + 10 + (3e – 10)/4 + 15 = 40

or (7e – 10)/4 = 15 or 7e = 70 or e = 10

Hence a = 5, c = 20, f = e = 10, d = 5

Hence the distribution is as follows

As per the observation of  class teacher actual numbers of students who lik

...more

New answer posted

3 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

According to the information provided in the statement following arrangement will be obtained:

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New question posted

3 months ago

0 Follower 1 View

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