Logical Reasoning
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New answer posted
8 months agoContributor-Level 10
(d)
The price of the 18 Pineapples with Shweta whose price is not known to us = X
X = 20 * 34 – (16 + 26 + 4 * 22 + 10 * 18) = Rs. 370
Assume that maximum number of Pineapples have price equal to 17
370 = 25 * 8 + 17 * 10. Number of pineapple with Shweta whose price is at least Rs. 25 is at most 8 + 1 = 9.
New answer posted
8 months agoContributor-Level 10
(d)
The total price of Mangoes with Shweta is 16 * 23 = Rs. 368.
Total price of 14 mangoes = 368 – (20 + 28) = Rs. 320
Out of the given 14 Mangoes assume that maximum number of Mangoes have price equal to Rs. 21.
The maximum price of any Mango out of these 14 Mangoes is Rs. 27
So, 9 * 21 + 1 * 23 + 4 * 27 = Rs. 320
Therefore, the number of Mangoes whose price is more than Rs. 21 is 1 + 4 + 1 = 6.
New answer posted
8 months agoContributor-Level 10
(a)
Total price of fruits with Shweta is 23 * 16 + 46 * 24 + 7 * 40 + 20 * 34 + 5 * 28 + 16 * 30 = Rs. 368 + Rs. 1104 + Rs. 280 + Rs. 680 + Rs. 140 + Rs. 480 = Rs. 3052. Total number of fruits with Shweta is 16 + 24 + 40 + 34 + 28 + 30 = 172. Average price of fruits with Shweta = (3052/172) = Rs. 17.74
New answer posted
8 months agoContributor-Level 10
| S1 | S2 | S3 | S4 | S5 | Total |
A1 | 97 | 99 | 98 | 98 | 99 | 491 |
A2 | 92 | 95 | 92 | 94 | 98 |
|
A3 | 86 | 89 | 85 | 90 | 93 | 443 |
A4 | 78 | 81 | 76 | 85 | 85 | 405 |
A5 | 66 | 69 | 64 | 75 | 75 | 349 |
A6 | 49 | 53 | 48 | 60 | 55 |
|
Total | 468 | 486 | 463 | 502 | 505 |
|
New answer posted
8 months agoContributor-Level 10
| S1 | S2 | S3 | S4 | S5 | Total |
A1 | 97 | 99 | 98 | 98 | 99 | 491 |
A2 | 92 | 95 | 92 | 94 | 98 |
|
A3 | 86 | 89 | 85 | 90 | 93 | 443 |
A4 | 78 | 81 | 76 | 85 | 85 | 405 |
A5 | 66 | 69 | 64 | 75 | 75 | 349 |
A6 | 49 | 53 | 48 | 60 | 55 |
|
Total | 468 | 486 | 463 | 502 | 505 |
|
New answer posted
8 months agoContributor-Level 10
| S1 | S2 | S3 | S4 | S5 | Total |
A1 | 97 | 99 | 98 | 98 | 99 | 491 |
A2 | 92 | 95 | 92 | 94 | 98 |
|
A3 | 86 | 89 | 85 | 90 | 93 | 443 |
A4 | 78 | 81 | 76 | 85 | 85 | 405 |
A5 | 66 | 69 | 64 | 75 | 75 | 349 |
A6 | 49 | 53 | 48 | 60 | 55 |
|
Total | 468 | 486 | 463 | 502 | 505 |
|
New answer posted
8 months agoContributor-Level 10
| S1 | S2 | S3 | S4 | S5 | Total |
A1 | 97 | 99 | 98 | 98 | 99 | 491 |
A2 | 92 | 95 | 92 | 94 | 98 |
|
A3 | 86 | 89 | 85 | 90 | 93 | 443 |
A4 | 78 | 81 | 76 | 85 | 85 | 405 |
A5 | 66 | 69 | 64 | 75 | 75 | 349 |
A6 | 49 | 53 | 48 | 60 | 55 |
|
Total | 468 | 486 | 463 | 502 | 505 |
|
New question posted
8 months agoNew question posted
8 months agoNew answer posted
8 months agoContributor-Level 10
Friends | Wives | Venue of wedding | Month |
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Manoj | Ipsita | Chennai | November |
Preet | Brinda | Mumbai | December |
Rajan | Hema | Delhi | April |
Sahil | Jasmine | Benguluru | September |
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