Logical Reasoning
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New answer posted
11 months agoContributor-Level 10
Name | Blue | Green | Red | Yellow | Salary |
Paul | * | ? | * | * | 30 |
Krishna | * | * | ? | * | 110 |
Laxman | * | * | * | ? | 50 |
Som | ? | * | * | * | 80 |
New question posted
11 months agoNew question posted
11 months agoNew answer posted
11 months agoContributor-Level 10
Professor | Day | Timing | Subject |
Mr. Singh | Friday | 07:10 | Set theory |
Mr. Chatterjee | Wednesday | 07:20 | Calculus |
Mr. Dutta | Monday | 07:00 | Probability |
Mr. Banerjee | Thursday | 07:05 | Ratio and Proportion |
New answer posted
11 months agoContributor-Level 10
Professor | Day | Timing | Subject |
Mr. Singh | Friday | 07:10 | Set theory |
Mr. Chatterjee | Wednesday | 07:20 | Calculus |
Mr. Dutta | Monday | 07:00 | Probability |
Mr. Banerjee | Thursday | 07:05 | Ratio and Proportion |
New answer posted
11 months agoContributor-Level 10
Professor | Day | Timing | Subject |
Mr. Singh | Friday | 07:10 | Set theory |
Mr. Chatterjee | Wednesday | 07:20 | Calculus |
Mr. Dutta | Monday | 07:00 | Probability |
Mr. Banerjee | Thursday | 07:05 | Ratio and Proportion |
New answer posted
11 months agoContributor-Level 10
Name | Game | Occupation | Floor | Age |
P | Tennis | Industrialist | 3 | the youngest (1) |
Q | Chess | Engineer | 3 | the oldest (5) |
R | Football |
|
| 6 |
S | Tennis |
| 2 | 4 |
T | Crickets |
|
| 2 |
New answer posted
11 months agoContributor-Level 10
Name | Game | Occupation | Floor | Age |
P | Tennis | Industrialist | 3 | the youngest (1) |
Q | Chess | Engineer | 3 | the oldest (5) |
R | Football |
|
| 6 |
S | Tennis |
| 2 | 4 |
T | Crickets |
|
| 2 |
From the above table Q is chess player and she is engineer option (A) is correct.
New answer posted
11 months agoContributor-Level 10
Name | Game | Occupation | Floor | Age |
P | Tennis | Industrialist | 3 | the youngest (1) |
Q | Chess | Engineer | 3 | the oldest (5) |
R | Football |
|
| 6 |
S | Tennis |
| 2 | 4 |
T | Crickets |
|
| 2 |
From the above table, Correct answer is option (A)
New answer posted
11 months agoContributor-Level 10
From the given condition g = 10,
Number of students who like both Physics and Maths = 10 + f
Number of students who like both chemistry and Maths = 10 + e
From given condition 10 + f = 10 + e or e = f
Similarly from 3rd condition ¾ (10 + e) = 10 + d
Or 30 + 3e = 40 + 4d
Or
Since 15 students like only chemistry hence b = 15
Number of students who like only chemistry is 40
Hence e + g + d + b = 40
or e + 10 + (3e – 10)/4 + 15 = 40
or (7e – 10)/4 = 15 or 7e = 70 or e = 10
Hence a = 5, c = 20, f = e = 10, d = 5
Hence the distribution is as follows
As per the observation of class teacher actual numbers of students who like Physics in
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