Logical Reasoning
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New answer posted
11 months agoContributor-Level 10
(d)
The cost of transportation for each options are:
(a) 300 * 28 = Rs. 8400
(b) 200 * 30 = Rs. 6000
(c) 300 * 15 = Rs. 4500
(d) 400 * 11 = Rs. 4400
Obviously, the cost of transportation of option (d) is the least.
New answer posted
11 months agoContributor-Level 10
(b)
Required cost
= (240 * 15) + (1200 * 30) + (840 * 18)
= Rs. 54720
New answer posted
11 months agoContributor-Level 10
(c)
F3 to W4 to R3 is maximum. Therefore, option (c) is the correct answer.
New answer posted
11 months agoContributor-Level 10
(c)
F4 to W4 to R4 is the lowest. Therefore, option (c) is the correct answer.
New answer posted
11 months agoContributor-Level 10
(b)
F5 to W1 to R5 is maximum. Therefore, option (b) is the correct answer.
New answer posted
11 months agoContributor-Level 10
(b)
F3 to W2 to R6 is the lowest. Therefore, option (b) is the correct answer.
New answer posted
11 months agoContributor-Level 10
Let us make a table for the time taken:
| Patna | Mumbai | Calcutta | Chennai | Bangalore |
Patna | - | 4 | 5 | 3.75 | 10 |
Mumbai | 4 | - | 6.666667 | 10 | 12.5 |
Calcutta | 5 | 6.666667 | - | 12.5 | 12 |
Chennai | 3.75 | 10 | 12.5 | - | 4 |
Bangalore | 10 | 12.5 | 12 | 4 | - |
c
New answer posted
11 months agoContributor-Level 10
Let us make a table for the time taken:
| Patna | Mumbai | Calcutta | Chennai | Bangalore |
Patna | - | 4 | 5 | 3.75 | 10 |
Mumbai | 4 | - | 6.666667 | 10 | 12.5 |
Calcutta | 5 | 6.666667 | - | 12.5 | 12 |
Chennai | 3.75 | 10 | 12.5 | - | 4 |
Bangalore | 10 | 12.5 | 12 | 4 | - |
a
New answer posted
11 months agoContributor-Level 10
Let us make a table for the time taken:
| Patna | Mumbai | Calcutta | Chennai | Bangalore |
Patna | - | 4 | 5 | 3.75 | 10 |
Mumbai | 4 | - | 6.666667 | 10 | 12.5 |
Calcutta | 5 | 6.666667 | - | 12.5 | 12 |
Chennai | 3.75 | 10 | 12.5 | - | 4 |
Bangalore | 10 | 12.5 | 12 | 4 | - |
(c)
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