Tags Maths

Maths

Get insights from 6.5k questions on Maths, answered by students, alumni, and experts. You may also ask and answer any question you like about Maths

Follow Ask Question

6.5k

Questions

Discussions

Active Users

Followers

New answer posted

3 months ago

Maths Statistics

How to work out probability from a frequency polygon?

0 Follower 2 Views

Jaya Sharma

Contributor-Level 10

Since a frequency polygon represents the data distribution, by interpreting the areas under curve, it is possible to infer probabilities for some range and interval. Let us take a look at it:

Understanding the Data: You must be able to comprehend the data represented by frequency polygon. In most cases, x-axis represents data values/intervals and y-axis represents frequency or relative frequency of those values.
Conversion to relative frequency: If frequency polygon is based on absolute frequencies, first convert it into relative frequency by dividing every frequency by total number of observations.
Identifying the area of interest: Then

...more

0 0

New answer posted

3 months ago

Maths Frequency Polygons

How many types of frequency polygons are there?

0 Follower 2 Views

Jaya Sharma

Contributor-Level 10

The following are different types of frequency polygons:

Simple Frequency Polygon: This is a standard form that connects the midpoints of tops of the bars in a histogram with straight lines.
Relative Frequency Polygon: This type of frequency polygon uses relative frequencies (proportions or percentages) instead of using absolute frequencies. This frequency polygon is used for comparing datasets of different sizes.
Cumulative Frequency Polygon (Ogives): Ogives are related and they represent cumulative frequencies. These can be used for showing the cumulative distribution of data and are used with frequency polygons.
Smoothed Frequency Polyg

...more

0 0

New answer posted

3 months ago

Maths Statistics

What are the advantages of frequency polygons?

0 Follower 7 Views

Jaya Sharma

Contributor-Level 10

The following points highlight the importance of frequency polygons:

Frequency polygons are useful for comparing distributions of multiple datasets on the same graph. It becomes easy to visually compare shapes and trends of different datasets by overlaying multiple frequency polygons.
These use lines to connect points which provide a continous representation of the data. It is easier to see patterns and trends over intervals through frequency polygons.
They can simplify the visualization of complex data which makes it easy to interpret the overshap and data distribution without distraction of bins or bars.
Line format of frequency polygon

...more

0 0

New answer posted

4 months ago

Maths Class 12th

The line of shortest distance between the lines $\frac{x - 2}{0} = \frac{y - 1}{1} = \frac{z}{1}$ and $\frac{x - 3}{2} = \frac{y - 5}{2} = \frac{z - 5}{1}$ makes an angle of $c o s^{- 1} (\sqrt[]{\frac{2}{27}})$ with the plane P : ax – y – z = 0, (a > 0). If the image of the point (1, 1, - 5) in the plane P is $(α, β, γ),$ then $α + β - γ$ is equal to……….

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

Line of shortest distance will be along ${\bar{b}}_{1} * {\bar{b}}_{2}$ $_{}_{}$

where $\begin{array}{l} _{} \end{array}$ $\begin{array}{l} {\bar{b}}_{1} = \hat{j} + \hat{k} \\ a n d \\ {\bar{b}}_{2} = 2 \hat{i} + 2 \hat{j} + \hat{k} \\ {\bar{b}}_{1} * {\bar{b}}_{2} = | \begin{matrix} \hat{i} & \hat{j} & \hat{k} \\ 0 & 1 & 1 \\ 2 & 2 & 1 \end{matrix} | = - \hat{i} + 2 \hat{j} - 2 \hat{k} \end{array}$

Angle between ${\bar{b}}_{1} * {\bar{b}}_{2}$ $_{}_{}$ and plane P,

$\Rightarrow a^{2} = - \frac{25}{11} (n o t p o s s i b l e)$

0 0

New answer posted

4 months ago

Maths Class 11th

The sum of diameters of the circles that touch (i) the parabola 75x² = 64(5y – 3) at the point $(\frac{8}{5}, \frac{6}{5})$ and (ii), the y-axis, is equal to………….

0 Follower 5 Views

Vishal Baghel

Contributor-Level 10

Equation of tangent to the parabola at

$P (\frac{8}{5}, \frac{6}{5})$

$75 x . \frac{8}{5} = 160 (y + \frac{6}{5}) - 192$

$\Rightarrow 120 x = 160 y$

$\Rightarrow 3 x = 4 y$

Equation of circle touching the given parabola at P can be taken as

$\Rightarrow λ = \frac{2}{5} o r - \frac{8}{5}$

Radius = 1 or 4

Sum of diameter = 10

0 0

New answer posted

4 months ago

Maths Class 11th

Le the equation of two diameters of a circle x² + y² -2x + 2fy + 1 = 0 be 2px – y = 1 and 2x + py = 4p. Then the slope $m \in (0, \infty)$ of the tangent to the hyperbola 3x² – y² = 3 passing through the centre of the circle is equal to………….

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$x^{2} + y^{2} - 2 x + 2 f y + 1 = 0 c e n t r e = (1, - f)$

diameter 2px – y = 1 ………. (i)

2x + py = 4p ……… (ii)

$x = \frac{5 P}{2 P^{2} + 2}$

f = 0

$[f o r P = \frac{1}{2}]$

$\frac{5 P}{2 P^{2} + 2} = 1$

f = 3 [for P = 2]

substitute (2, 3)

$3 = m \pm \sqrt[]{m^{2} - 3}$

$∴ m = 2$

0 0

New answer posted

4 months ago

Maths Class 12th

If $\underset{n \to \infty}{l i m} \frac{{(n + 1)}^{k - 1}}{n^{k + 1}} [(n k + 1) + (n k + 2) + . . . . + (n k + n)]$

$= 33 . \underset{n \to \infty}{l i m} \frac{1}{n^{k + 1}} .$ $[1^{k} + 2^{k} + 3^{k} + . . . + n^{k}]$ , then the integral value of k is equal to…………

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$l i m_{n \to \infty} {(\frac{n + 1}{n})}^{k - 1} \frac{1}{n} \sum_{r = 1}^{n} (k + \frac{r}{n})$

= $33 \int_{0}^{1} x^{k} d x$

0 0

New answer posted

4 months ago

Maths Class 12th

Let f(x) = ${\begin{matrix} | 4 x^{2} - 8 x + 5 |, i f 8 x^{2} - 6 x + 1 \geq 0 & [4 x^{2} - 8 x + 5], i f 8 x^{2} - 6 x + 1 < 0 \end{matrix}}$ , where [a] denotes the greatest integer less than or equal to a. Then the number of points in R where f is not differentiable is………….

0 Follower 5 Views

Vishal Baghel

Contributor-Level 10

$f (x) = {\begin{cases} | 4 x^{2} - 8 x + 5 |, i f 8 x^{2} - 6 x + 1 \geq 0 \\ [4 x^{2} - 8 x + 5], i f 8 x^{2} - 6 x + 1 < 0 \end{cases}$

$x = \frac{1}{4}, \frac{2 - \sqrt[]{2}}{2}, \frac{1}{2}$

0 0

New answer posted

4 months ago

Maths Class 11th

let a₁ = b₁ = 1, a_n = a_n-1 + 2 and b_n = a_n + b_n-1 for every natural number $n \geq 2 .$ Then $\sum_{n = 1}^{15} a_{n} . b_{n}$ is equal to………….

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

a₁ = b₁ = 1

$a_{n} = a_{n - 1} + 2 (f o r n \geq 2) b_{n} = a_{n} = b_{n - 1}$

Similarly for others

$\sum_{n = 1}^{11} a_{n} b_{n} = \sum_{n = 1}^{15} (2 n - 1) n^{2} = \sum_{n = 1}^{15} 2 n^{3} - \sum_{n = 1}^{15} n^{2}$

$= 2 {[\frac{15 * 16}{2}]}^{2} - [\frac{15 * 16 * 31}{6}] = 27560$

0 0

New answer posted

4 months ago

Maths Class 11th

Let a, b be two non-zero real numbers. If p and r the roots of the equation x² - 8zx + 2a = 0 and q and the roots of the equation x² + 12bx + 6b = 0, such that $\frac{1}{p}, \frac{1}{q}, \frac{1}{r}, \frac{1}{s}$ are in A.P., then a^-1 – b^-1 is equal to…………

0 Follower 4 Views

Vishal Baghel

Contributor-Level 10

$?$ Roots of 2ax² - 8 ax + 1 = 0 are

$\frac{1}{p} a n d \frac{1}{r}$ and roots of 6bx² + 12bx + 1 = 0 are

$\frac{1}{q} a n d \frac{1}{8}$

Let $\frac{1}{p}, \frac{1}{q}, \frac{1}{r}, \frac{1}{8}$

as $α - 3 β, α - β, α + β, α + 3 β$

$S o, \frac{1}{a} - \frac{1}{b} = 38$

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
679k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Maths

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience